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V125BC [204]
2 years ago
15

Calculate the heat required to melt 25.7 g of solid methanol at its melting point

Chemistry
2 answers:
gulaghasi [49]2 years ago
7 0

Answer:

the heat required to melt the compound is 2.56k

umka2103 [35]2 years ago
4 0

The heat required to melt the compound is<u> 2.56kJ.</u>

Why?

To calculate the heat required to melt 25.7 g of solid methanol, we need to calculate its molar mass, know its chemical formula, its molar heat of fusion, and calculate how many moles represent 25.7g of the same compound.

Then, we need to use the following formula to calculate the heat:

Q=N*u

Where,

N is the moles of the compound

u, is the molar heat of fusion of the compound (J/mol)

We know that the molar mass of methanol is :

32.042\frac{g}{mol}

So, we can calculate the number of moles that represents 25.7g of the same compound:

N=\frac{mass(g)}{molarmass(\frac{g}{mol}} \\\\N=\frac{25.7g}{32.042\frac{g}{mol}}=0.8mol(methanol)

Also, the molar heat of fusion of methanol is:

u_{methanol}=3200\frac{J}{mol}=3.2\frac{kJ}{mol}

Now, substituting into the first equation and calculating, we have:

Q=N*u

Q=0.8mol*3.2\frac{kJ}{mol}=2.56kJ

Hence, we have that the heat required to melt the compound is 2.56kJ.

Have a nice day!

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Answer : The equilibrium SO_2 pressure is, 3.93\times 10^{-5}torr

Explanation :

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\Delta G^o=[n_{S(s)}\times \Delta G_f^0_{(S(s))}+n_{H_2O(g)}\times \Delta G_f^0_{(H_2O(g))}]-[n_{SO_2(g)}\times \Delta G_f^0_{(SO_2(g))}+n_{H_2S(g)}\times \Delta G_f^0_{(H_2S(g))}]

where,

\Delta G^o = standard free energy of reaction = ?

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Now put all the given values in this expression, we get:

\Delta G^o=[3mole\times (0kJ/mol)+2mole\times (-228.57kJ/mol)]-[1mole\times (-300.4kJ/mol)+2mole\times (-33.01kJ/mol)]

\Delta G^o=-90.72kJ/mol

Now we have to calculate the value of K_p

\Delta G^o=-RT\ln K_p

where,

\Delta G_^o =  standard Gibbs free energy  = -90.72 kJ/mol

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-90.72kJ/mol=-(8.314J/mol.K)\times (298K) \ln K_p

K_p=7.98\times 10^{15}

Now we have to calculate the value of K_p.

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The expression for equilibrium constant will be :

K_p=\frac{(p_{H_2O})^2}{(p_{H_2S})^2\times (p_{SO_2})}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Let the equilibrium SO_2 pressure be, x

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7.98\times 10^{15}=\frac{(22)^2}{(x)^2\times (x)}

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