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V125BC [204]
2 years ago
15

Calculate the heat required to melt 25.7 g of solid methanol at its melting point

Chemistry
2 answers:
gulaghasi [49]2 years ago
7 0

Answer:

the heat required to melt the compound is 2.56k

umka2103 [35]2 years ago
4 0

The heat required to melt the compound is<u> 2.56kJ.</u>

Why?

To calculate the heat required to melt 25.7 g of solid methanol, we need to calculate its molar mass, know its chemical formula, its molar heat of fusion, and calculate how many moles represent 25.7g of the same compound.

Then, we need to use the following formula to calculate the heat:

Q=N*u

Where,

N is the moles of the compound

u, is the molar heat of fusion of the compound (J/mol)

We know that the molar mass of methanol is :

32.042\frac{g}{mol}

So, we can calculate the number of moles that represents 25.7g of the same compound:

N=\frac{mass(g)}{molarmass(\frac{g}{mol}} \\\\N=\frac{25.7g}{32.042\frac{g}{mol}}=0.8mol(methanol)

Also, the molar heat of fusion of methanol is:

u_{methanol}=3200\frac{J}{mol}=3.2\frac{kJ}{mol}

Now, substituting into the first equation and calculating, we have:

Q=N*u

Q=0.8mol*3.2\frac{kJ}{mol}=2.56kJ

Hence, we have that the heat required to melt the compound is 2.56kJ.

Have a nice day!

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The principal component of mothballs is naphthalene, a compound with a molecular mass of about 130 amu, containing only carbon a
DIA [1.3K]

Answer:

Empirical formula = C5H4

Molecular formula = C10H8

Explanation:

When the 3000 mg of naphthalene are burned they produce 10.3 mg of CO2. Knowing the unbalanced equation of the combustion of naphthalene, we have:

CxHy + O2 = CO2 + H2O

We calculate the molar composition of the sample. We look for the molecular weights in the periodic table:

CO2 = 12,011 + 2 (15,999) = 44,009 g

Mol C = 10.3 mg * (1 mol CO2 / 44.009 g CO2) * (1 mol C / 1 mol CO2) = 0.234 mmol C

Mass C = 0.234 mmol C * (12.011 g C / 1 mol C) = 2.8105 mg C

Mass H = 3 mg - 2.8105 mg = 0.1895 mg H

Mol H = 0.1895 mg H * (1 mol H / 1,008 g H) = 0.188 mmol H

To calculate the empirical formula, we must divide the number of moles of each element by the smallest number of moles, in this case, of hydrogen:

C = 0.2340 mmol C / 0.1895 mol H = 1.25

H = 0.1895 mmol H / 0.1895 mmol H = 1

We multiply the coefficients by 4, and we have the empirical formula:

C1.25 * 4H1 * 4 = C5H4

The molecular formula is equal to (C5H4)m, where m is calculated by the molecular and empirical mass ratio, as follows:

Empirical mass = (5 * 12.011) + (4 * 1.008) = 64.09 g

m = 130 g / 64.09 g = 2.02 = 2

Therefore we have the molecular formula:

(C5H4)2 = C10H8

4 0
2 years ago
Which are examples of equilibrium? Check all that apply.
Sveta_85 [38]

I believe that the answers are 3 and 4

4 0
1 year ago
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Design a synthesis of 2-ethyl-2-hexenoic acid from alcohols of four carbons or fewer.
Studentka2010 [4]

Answer:

Enolate Alkylation

The anions from ketones, called enolates, can act as a nucleophile in SN2 type reactions.  Overall an α hydrogen is replaced with an alkyl group and a new carbon-carbon bond is formed.  These alkylations are affected by the same limitations as SN2 reactions previously discussed.  A good leaving group, chloride, bromide, iodide or tosylate, should be used.  Also, secondary and tertiary leaving groups should not be used because of poor reactivity and possible competition with elimination reactions.  Lastly, it is important to use a strong base, such as LDA or sodium amide, for preparing the enolate from the ketone.  Using a weaker base such as hydroxide or an alkoxide leaves the possibility of multiple alkylations occurring, and competing SN2 reactions with the base.

Explanation:

Design is illustrated in the attached document

4 0
2 years ago
Select the simplest mole ratio for each substance. Glucose (C6H12O6): Sulfuric acid (H2SO4): Butene (C4H8):
Rom4ik [11]

<u>Answer:</u>

1. In Glucose: C : H : O = 1 : 2 : 1

2. In Sulfuric acid: H : S : O = 2 : 1 : 4

3. In Butene: C : H = 1 : 2

<u>Explanation:</u>

Mole ratio is defined as the ratio of amounts in moles present in a compound. Simplest mole ratio basically means that the moles are present in the least whole number ratio.

  • In Glucose, (C_6H_{12}O_6)

Moles of Carbon atom = 6

Moles of Hydrogen atom = 12

Moles of Oxygen atom = 6

Mole ratio of the atoms: C : H : O :: 6 : 12 : 6

Making this, the simplest mole ratio C : H : O = 1 : 2 : 1

  • In Sulfuric acid, (H_2SO_4)

Moles of Sulfur atom = 1

Moles of Hydrogen atom = 2

Moles of Oxygen atom = 4

Mole ratio of the atoms: H : S : O = 2 : 1 : 4

  • In Butene, (C_4H_8)

Moles of Carbon atom = 4

Moles of Hydrogen atom = 8

Mole ratio of the atoms: C : H = 1 : 2

8 0
2 years ago
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Please help with these three questions.
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3 0
2 years ago
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