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erik [133]
2 years ago
8

The Sun is a main sequence star. During the last stage of its life cycle, it will become a white dwarf. It will shrink in size,

but it will be very hot. Which of the stars in your chart do you think is a white dwarf and why?
Chemistry
2 answers:
kramer2 years ago
4 0

Answer:

The ones with an absolute magnitude that is more than 5 and have a surface temperature between 25,000 and 7,500.

Barnard's star and  Proxima Centauri because their absolute magnitude is more than 5 and they have a surface temperature of 25,000 7,500.

Explanation: For edmentum users

dangina [55]2 years ago
3 0
The one that is tiny and white. 
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What is the overall charge of the compound frbr
sammy [17]

Answer:

Zero  

Explanation:

FrBr is an ionic compound .

Fr is in Group 1. Br is in Group 17.

The charges on the ions are +1 and -1, respectively.

The compound consists of Fr⁺Br⁻ ions.

However, there are equal numbers of + and - charges, so

The overall charge of the compound is zero.

5 0
2 years ago
What volume will 6.745g of neon gas occupy at standard temp and pressure?
Thepotemich [5.8K]
First, multiply the mass by the molar mass of neon to find out how many moles of neon there are. Then, multiply by 22.4 to find out how many liters there are.

6.745g Ne x 1 mole Ne/20 g Ne x 22.4 L/1 mole Ne = 7.5544 L
4 0
2 years ago
Read 2 more answers
A beach has a supply of sand grains composed of calcite, ferromagnesian silicate minerals, and non-ferromagnesian silicate miner
bezimeni [28]
Ferromagnesian silicate minerals (i looked it up)
4 0
2 years ago
0.50 mol A, 0.60 mol B, and 0.90 mol C are reacted according to the following reaction
algol [13]

Reactant C is the limiting reactant in this scenario.

Explanation:

The reactant in the balanced chemical reaction which gives the smaller amount or moles of product is the limiting reagent.

Balanced chemical reaction is:

A + 2B + 3C → 2D + E

number of moles

A = 0.50 mole

B = 0.60 moles

C = 0.90 moles

Taking A as the reactant

1 mole of A reacted to form 2 moles of D

0.50 moles of A will produce \frac{2}{1} = \frac{x}{0.50}

thus 0.50 moles of A will produce 1 mole of D

Taking B as the reactant

2 moles of B reacted to form 2 moles of D

0.60 moles of B reacted to form x moles of D

\frac{2}{2} = \frac{x}{0.6}

x = 2 moles of D is produced.

Taking C as the reactant:

3 moles of C reacted to form 2 moles of D

O.9 moles of C reacted to form x moles of D

\frac{2}{3} = \frac{x}{0.9}

= 0.60 moles of D is formed.

Thus C is the limiting reagent in the given reaction as it produces smallest mass of product.

5 0
2 years ago
What is the amount of Al2S3 remains when 20.00 g of Al2S3 and 2.00 g of H2O are reacted? A few of the molar masses are as follow
Irina18 [472]
From the equation, we can tell that 1 mol of Al₂S₃ requires 6 moles of water.
The molar ratio is 1/6
Moles of Al₂S₃ present = 20/150.17
= 0.133
Moles of water present = 2/18.02
= 0.111
The moles of Al₂S₃ that will react are:
0.111/6
= 0.0185
The remaining amount:
0.133 - 0.0185
= 0.1145 mol
Or
0.1145 * 150.17
= 17.19 grams
6 0
2 years ago
Read 2 more answers
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