Answer:
b. 295 pm
Explanation:
To answer this question we need to use the equation of a face-centered cubic laticce:
Edge length = √8 R
<em>Where R is radius of the atom.</em>
<em />
Replacing:
417pm = √8 R
R = 147.4pm is the radius of the atom
As diameter = 2 radius.
Diameter of the metal atom is:
147.4pm* 2 =
295pm
Right answer is:
<h3>b. 295 pm
</h3>
Its period 5 from 5s25p6, with Xenon(54) as the noble gas. 2+6 = 8 electrons
54+8 = 62, or Sm.
Answer:
b
. Irradiated food is shown to not be radioactive.
Explanation:
If it can be proven that irradiated food is not radioactive, then it will effective dispute the idea that irradiated food are less safe to eat.
- An irradiated food is one in which ionizing radiations have been employed to improve food quality.
- Thus, bacteria and other food spoilers can be exterminated from the food.
- Most irradiated food do not contain radiation and are fit for consumption.
If it can be proven, that this is true, then it will challenge the idea that irradiated foods are not safe.
Answer:
CO = zero
CO2 =1 bar
O2 = 2.02 bar
Explanation:
We are given
initial pressure of CO = 1bar
total pressure = 3.52 bar
so initial pressure of O2 = 3.52 - 1 = 2.52 bar
the reaction is
2CO + O2 → 2CO2
using the unitary method
2 moles of CO2 → 1 mole of O2
1 bar of CO → 
(required)
but we have more oxygen present , that means CO is the limiting reagent
- Final pressure of CO will be zero as it is the limiting reagent so it will be consumed completely
- 1 bar of CO →
of CO2 - 2.52 bar O2 (initially) - 0.5 bar (reacted) = 2.02bar O2
Convert grams —> mols and then mols —> atoms
We know that there are 6.02 x 10^23 atoms/mol
And we know that there are about 160 grams of fe2o3 per mol
So (79g fe2o3)/(160 g/mol) = .49 mol fe2o3
Now we use avogadro’s number to do
(.49 mol fe2o3)/(6.02 x 10^23 atoms/mol) = the answer.
I’ll leave the easy math to you.
