Explanation:
The given data is as follows.
= 30.0 sec, 
= 5 min = 
= 300 sec
= 12.0 min = 
= 720 sec
Formula for adjusted retention time is as follows.
= 300 sec - 30.0 sec
= 270 sec
= 720 sec - 30 sec
= 690 sec
Formula for relative retention (
) is as follows.
= 
= 2.56
Thus, we can conclude that the relative retention is 2.56.
To determine the number of gas particles in the vessel we add all of the components of the gas. For this, we need to convert the mass to moles by the molar mass. Then, from moles to molecules by the avogadro's number.
1.50x10^-6 ( 1 / 28.01) (6.022x10^23) = 3.22x10^16 molecules CO
6.80x10^-6 ( 1 / 2.02) (6.022x10^23) = 2.03x10 18 molecules H2
Totol gas particles = 2.05x10^18 molecules
The value of X is 10 hence the formula of unknown hydrate sodium sulfate is NaSO4.10 H20
calculation
step 1:find the moles of NaSO4 and the moles of H2O
moles= mass/molar mass
moles of Na2SO4=1.42÷142=0.01 moles
moles of H20= mass of H2O/molar mass of H2O
mass of H2O= 3.22-1.42=1.8g
mole of H2O is therefore 1.8÷18=0.1 moles
step 2: find the mole ratio by dividing each mole by smallest number of mole (0.01)
that is Na2So4= 0.01/0.01 =1
H2O= 0.1/0.01=10
The reaction is given as:
Here, two moles of copper nitrate reacts with four moles of potassium iodide to give two moles of copper iodide, one mole of iodine and four moles of potassium nitrate.
First, calculate the number of moles of copper nitrate.
Number of moles is equal to the product of molarity and volume of solution in litre.
Number of moles = 
(1 L =1000 mL)
= 
Copper nitrate requires = 
mole of potassium iodide
= 
of potassium iodide
Volume of solution in litre = 
Thus, volume of potassium iodide is =
= 
1 L =1000 mL
Volume of potassium iodide in mL =
Hence, 0.2089 M potassium iodide consist of sufficient potassium iodide to react with copper nitrate in 3.88 mL of a 0.3842 M solution of copper nitrate .
Answer:
2s²2p⁴
Explanation:
Oxygen is an element on the periodic table with a total of 8 electrons. It's electronic configuration is given as 2,6.
Using the orbital notation we write as 1s²2s²2p⁴
Also, the valence electrons are the electrons in the outermost shell of an atom. These electrons mostly determine the chemical properties of an atom.
Oxygen has a total of 6 electrons in its outermost shell and it is given as 2s²2p⁴
