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Arte-miy333 [17]
2 years ago
10

Why would early Earth have been toxic for modern day animals? Why were cyanobacteria able to

Chemistry
1 answer:
Oksanka [162]2 years ago
5 0

Answer: The surface of early earth was mostly molten and volcanic. The atmosphere was hot and highly toxic.

Explanation: Photosynthetic organisms were present when earth was primarily anoxic. photosynthetic organisms were present when earth was primarily anoxic. the early forms of photosynthesis did not produce oxygen as a waste product. cyanobacteria carry out anoxic photosynthesis. the early forms of photosynthesis did produce oxygen, but it was not enough to make a difference in the atmosphere. the early forms of photosynthesis were carried out in the water, and there was no way for the oxygen to move into the atmosphere.

1

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The speed of light in a vacuum is 2.998 × 10 8 8 m/s. How long does it take for light to circumnavigate the Earth, which has a c
svp [43]

Answer:- 0.134 seconds

Solution:- The speed is given as 2.988*10^8\frac{m}{s} and the circumference is 24900 miles which is same as the distance light have to covered. It asks to calculate the time required to cover this distance by the light.

We need to do unit conversion from miles to meter as the speed is given in meter per second.

1 mile = 1609.34 meter

So, 24900mile(\frac{1609.34meter}{mile})

= 40072566 meters

Know that, speed=\frac{distance}{time}

It's rearranged to time as, time=\frac{distance}{speed}

Let's plug in the values in it:

time=\frac{40072566meter}{2.988*10^8\frac{meter}{second}}

= 0.134 seconds

So, the light would take 0.134 seconds to travel the mentioned speed. The answer without the unit is 0.134.

8 0
1 year ago
A double-replacement reaction takes place when aqueous k2so4 reacts with aqueous pb(no3)2. you would expect the products of this
SpyIntel [72]
A double replacement is when the reactants switch with their opposite charge. For example, AB + CD = AD + BC.

In this case the given is K2SO4 + Pb(NO3)2 = ____ + ____

The answers is PbSO4 and KNO3 would expect the products of this reaction.
8 0
2 years ago
Read 2 more answers
2Na2O2 + 2CO2 → 2Na2CO3 + O2
ahrayia [7]

the actual yield is the amount of Na₂CO₃ formed after carrying out the experiment

theoretical yield is the amount of Na₂CO₃ that is expected to be formed from the calculations

we need to first find the theoretical yield

2Na₂O₂ + 2CO₂ ---> 2Na₂CO₃ + O₂

molar ratio of Na₂O₂ to Na₂CO₃ is 2:2

number of Na₂O₂ moles reacted is equal to the number of Na₂CO₃ moles formed

number of Na₂O₂ moles reacted is - 7.80 g / 78 g/mol = 0.10 mol

therefore number of Na₂CO₃ moles formed is - 0.10 mol

mass of Na₂CO₃ expected to be formed is - 0.10 mol x 106 g/mol = 10.6 g

therefore theoretical yield is 10.6 g

percent yield = actual yield / theoretical yield  x 100%

81.0  % = actual yield / 10.6 g x 100 %

actual yield = 10.6 x 0.81

actual yield = 8.59 g

therefore actual yield is 8.59 g

7 0
2 years ago
Read 2 more answers
How many moles of gas are present in 57.20 L of argon at a pressure of 1 atm and a temperature of 0°C?
slamgirl [31]

Answer:

n= 2.55 moles

Explanation:

Using the formula of ideal gas law:

PV = nRT

  nRT=PV

n= PV/RT

  n= number of moles

  R= Avogadro constant = 0.0821

  T= Temperature in K => ºC + 273.15 K

  V= volume in L

  P= pressure in atm

n= (1 atm)(57.20 L) / (0.0821)(237.15 K)

n= 2.50 moles

3 0
2 years ago
Calculate the mass in grams of each of the following amounts: 1.002 mol of chromium 4.08 x 10-8 mol of neon
Pepsi [2]

Answer:

Mass_{chromium}=52.1\ g

Mass_{neon}=8.23\times 10^{-7}\ g

Explanation:

<u>Calculation of the mass of chromium as:- </u>

Moles = 1.002 moles

Molar mass of chromium = 51.9961 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

1.002\ mol= \frac{Mass}{51.9961\ g/mol}

Mass_{chromium}=1.002\times 51.9961\ g = 52.1\ g

<u>Calculation of the mass of neon as:- </u>

Moles = 4.08\times 10^{-8} moles

Molar mass of neon = 20.1797 g/mol

Thus,

1.002\ mol= \frac{Mass}{20.1797\ g/mol}

Mass_{neon}=4.08\times 10^{-8}\times 20.1797\ g = 8.23\times 10^{-7}\ g

6 0
2 years ago
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