Sorenson
Explanation:
The values used in the scale of pH and pOH are derived from a system designed by Sorenson. Søren Peter Lauritz Sørensen, a Danish chemist introduced the system of pH and pOH for describing the alkalinity and acidity of substances.
- The pH and pOH scale is logarithmic scale that ranks the acidity and bascity of compounds.
- pH is the negative logarithm of the concentration of hydrogen/hydroxonium ions in solution i.e
pH = -log₁₀{H⁺]
- pOH is the negative log of the concentration of the hydroxyl ions in a solution i.e
pOH = -log₁₀{OH⁻]
Learn more:
calculating pH: brainly.com/question/12985875
pH scale: brainly.com/question/11063271
#learnwithBrainly
First one. Coefficients are numbers that balance the equation, just like if there is an equation in math where 1=2, you need to multiply 1 by 2 to make that equation true. That's a nice jingle you can remember.
The most important question for the students to answer is what the discovery did to society. Did it change society in any way or better something?
Answer:
Explanation:
first write the equilibrium equaion ,
⇄ 
assuming degree of dissociation 
=1/10;
and initial concentraion of =c;
At equlibrium ;
concentration of 
![[C_3H_5O_3^{-} ]= c\alpha](https://tex.z-dn.net/?f=%5BC_3H_5O_3%5E%7B-%7D%20%20%5D%3D%20c%5Calpha)
![[H^{+}] = c\alpha](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%20c%5Calpha)
is very small so 
can be neglected
and equation is;
= 
![P_H =- log[H^{+} ]](https://tex.z-dn.net/?f=P_H%20%3D-%20log%5BH%5E%7B%2B%7D%20%5D)
composiion ;
![c=\frac{1}{\alpha} \times [H^{+}]](https://tex.z-dn.net/?f=c%3D%5Cfrac%7B1%7D%7B%5Calpha%7D%20%5Ctimes%20%5BH%5E%7B%2B%7D%5D)
![[H^{+}] =antilog(-P_H)](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3Dantilog%28-P_H%29)
![[H^{+} ] =0.0014](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%20%5D%20%3D0.0014)
Answer:
14.5L
Explanation:
The following data were obtained from the question:
V1 = 14.1L
T1 = 13.9°C = 13.9 + 273 = 286.9K
T2 = 22°C = 22 + 273 = 295K
V2 =?
Using charles' law: V1/T1 = V2 /T2, we can obtain the new volume as follows:
14.1/286.9 = V2 /295
Cross multiply to express in linear form
286.9 x V2 = 14.1 x 295
Divide both side by 286.9
V2 = (14.1 x 295) / 286.9
V2 = 14.5L
Therefore, the new volume = 14.5L
