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mrs_skeptik [129]
1 year ago
11

Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coeffici

ent is "1".
NH3 + F2 → N2F4 + HF
Chemistry
2 answers:
Sveta_85 [38]1 year ago
8 0
2 NH3 + 5F2 = blank N2F4 + 6 HF
erica [24]1 year ago
3 0

Answer : The balanced chemical reaction will be,

2NH_3+5F_2\rightarrow N_2F_4+6HF

Explanation :

Balanced chemical reaction : It is defined as the chemical reaction in which the number of individual atoms of an element in reactant side always be equal to the number of individual atoms of an element in product side.

The given balanced reaction will be,

2NH_3+5F_2\rightarrow N_2F_4+6HF

By the stoichiometry we can say that, 2 moles of NH_3 react with 5 moles of F_2 to give 1 mole of N_2F_4 and 6 moles of HF as a product.

Hence, the balanced chemical reaction will be,

2NH_3+5F_2\rightarrow N_2F_4+6HF

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A student is given two 10g samples, each a mixture of only NaCl(s) and KCl(s) but in different proportions. Which of the followi
8090 [49]

Answer:

The information that can be used to determine which mixture has the higher proportion of KCl IS INFORMATION ABOUT THE MASS OF CHLORINE IN EACH MIXTURE, THIS INFORMATION CAN BE OBTAINED BY USING THE LAW OF DEFINITE PROPORTION.

Explanation:

The law of definite proportion states that the chemical composition by mass of a chemical compound is always constant. For instance, a chemical compound that is made up of two elements will always contain the same proportions of the constituent elements regardless of the quantity of chemical that was used.

Using the law of definite proportion, we can determine the proportion of sodium and chlorine in NaCl and the proportion of potassium and chlorine in KCl if the mass of chlorine that was used is known. Based on the results obtained, one can easily determine the mixtures that has higher proportion of KCl.

6 0
2 years ago
Read 2 more answers
Octane (C8H18) is a component of gasoline. Complete combustion of octane yields H2O and CO2. Incomplete combustion produces H2O
mestny [16]

86.5\; \% of octane had been converted to carbon dioxide CO₂.

<h3>Explanation</h3>

Octane has a molar mass of

12.01 \times 8 + 1.008 \times 18 = 114.22 \; \text{g} \cdot \text{mol}^{-1}

1.000 gallon of this fuel would have a mass of 2.650 kilograms or 2.65 \times 10^{3} \; \text{g}, which corresponds to 2.65 \times 10^{3} / 114.22 = 23.2\; \text{mol} of octane.

Octane undergoes complete combustion to produce carbon dioxide and water by the following equation:

2\; \text{C}_8\text{H}_{18} + 25 \; \text{O}_2 \to 16 \; \text{CO}_2 + 18 \; \text{H}_2\text{O}

An incomplete combustion of octane that gives rise to carbon monoxide and water but no carbon dioxide would consume not as much oxygen:

2\; \text{C}_8\text{H}_{18} + 17 \; \text{O}_2 \to 16 \; \text{CO} + 18 \; \text{H}_2\text{O}

The mass of the product mixture is 11.53 - 2.65 = 8.88 \; \text{kg} heavier than that of the octane supplied. Thus 8.88 \; \text{kg} = 8.88 \times 10^{3} \; \text{g} of oxygen were consumed in the combustion. There are 277.5 \; \text{mol} of oxygen molecules in 8.88 \times 10^{3} \; \text{g} of oxygen.

Let the number of moles of octane that had undergone complete combustion as seen in the first equation be x (0 \le x \le 23.2). The number of moles of octane that had undergone incomplete combustion through the second equation would thus equal 23.2 - x.

25 moles of oxygen gas is consumed for every two moles of octane that had undergone complete combustion and 17 moles if the combustion is incomplete.

n(\text{O}_2, \; \text{Complete Combustion}) + n(\text{O}_2, \; \text{Incomplete Combustion} ) = n(\text{O}_2, \; \text{Consumed})\\

\frac{25}{2} \; x + \frac{17}{2} \; (23.2 - x) = 277.5\\4 \; x = 277.5 - \frac{17}{2} \times 23.2\\x = 20.1

Therefore 20.1 \; \text{mol} out of the 23.2 moles of octane had undergone complete combustion to produce carbon dioxide.

\%n(\text{Complete Combustion}) = 20.1 / 23.2 \times 100 \; \%= 86.5\; \%

7 0
1 year ago
Calculate the pressure exerted by 66.0 g of CO2 gas at -14.5°C that occupies a volume of 50.0 L
Anestetic [448]

Answer:

Pressure = 0.64 atm

Explanation:

Use Ideal Gas Law PV = nRT => P = nRT/V

n = moles CO₂(g) = 66g/44g/mol = 1.5 mol CO₂

R = Gas Constant = 0.08206 L·atm/mol·K

T = Temperature = -14.5°C = (-14.5 + 273)K = 258.5 K

V = 50.0 Liters

P = (1.5 mol)(0.08206 L·atm/mol·K)(258.5 K)/(50.0 L) = 0.64 atm

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How many joules are absorbed in a process that absorbs 0.5720 kcal?
nadya68 [22]
Both joules and kilocalories are units of measurement for energy. This means that the solution to this problem can be solved just by converting the units using the appropriate conversion factors. One kilocalorie is equal to 4,184 joules. Multiply 0.5720 kcal by 4,184 to get the value in joules. This gives 2,393.25 joules.
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1 year ago
You decide to place a bottle of water into the freezer so it will stay cold all day at school. Which of the following accurately
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Answer:c

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