Answer : 1721.72 g/qt are in 18.2 g/cL
Explanation :
As we are given: 18.2 g/cL
Now we have to convert 18.2 g/cL to g/qt.
Conversions used are:
(1) 1 L = 100 cL
(2) 1 L = 1000 mL
(3) 1 qt = 946 qt
The conversion expression will be:
Therefore, 1721.72 g/qt are in 18.2 g/cL
Answer:
The number on the lag label should be 15.
Explanation:
It seems your question is incomplete, as it is lacking the working values. An internet search showed me the full question, you can see it in the attached picture.
Let's say we have 100 g of the fertilizer.
(We used the molar mass of ammonium phosphate in the denominator and three times the molar mass of nitrogen in the numerator)
So in total there are (12.7+2.73) 15.43 g of Nitrogen in 100 g of the fertilizer. So the percent by mass of nitrogen is 15.43%.
Rounding to the nearest percent the answer is 15.
<u>Answer:</u>
<u>For a:</u> Lead iodide is a yellow precipitate.
<u>For b:</u> Barium sulfate is a white precipitate.
<u>For c:</u> Ferric hydroxide is a brown precipitate.
<u>For d:</u> Copper (II) hydroxide is a blue precipitate.
<u>Explanation:</u>
Precipitation reaction is defined as the reaction where a solid precipitate (solid substance) is formed at the end of the reaction. It is insoluble in water.
For the given options:
The chemical reaction between KI and lead (II) nitrate follows:
The iodide of lead is generally insoluble in water. Thus, lead iodide is a yellow precipitate.
The chemical reaction between barium chloride and sulfuric acid follows:
The sulfate of barium is insoluble in water. Thus, barium sulfate is a white precipitate.
The chemical reaction between NaOH and ferric chloride follows:
The hydroxide of iron is insoluble in water. Thus, ferric hydroxide is a brown precipitate.
The chemical reaction between NaOH and copper sulfate follows:
The hydroxide of copper is insoluble in water. Thus, copper (II) hydroxide is a blue precipitate.