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Bess [88]
2 years ago
15

Compare and contrast the number of representative particles and the mass of UF6 with the number of representative particles and

mass of CCl3CF3. Explain any differences you observe.
Chemistry
2 answers:
Anettt [7]2 years ago
4 0
A representative particle is the smallest unit of a specific substance that can be found in nature. These are typically in forms of atoms. However, may also be in compounds, etc. The number of representative particle of UF6, I believe is 1 with a molar mass of 352.02 g/mol same with CCl3CF3 with a mass of 187.35 g/mol. 
sweet [91]2 years ago
3 0

Answer:

Particles_{UF_6}=3.85x10^{23}particles\\\\Particles_{CCl_3CF_3}=6.43x10^{23}particles

Explanation:

Hello,

In this case, since the given masses of UF6 and CCl3CF3 are 225 g and 200 g respectively (missing information) if we want to compare and contrast the number of representative particles both the molar mass for those compounds (352.02g/mol and 187.3756g/mol respectively) and the Avogrado's number must be used as follows:

Particles_{UF_6}=225g*\frac{1molUF_6}{352.02gUF_6}*\frac{6.022x10^{23}particles}{1molUF_6}=3.85x10^{23}particles\\\\Particles_{CCl_3CF_3}=225g*\frac{1molCCl_3CF_3}{187.3756gCCl_3CF_3}*\frac{6.022x10^{23}particles}{1molCCl_3CF_3}=6.43x10^{23}particles

In such a way, one sees that since it is about different compounds having different molar masses, but in order to know the number of representative particles, the same Avogadro's number is used, the results are quite different and is evident just by the simple fact that they are different compounds.

Best regards.

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Basile [38]

Answer:

Mole fraction of methanol will be closest to 4.

Explanation:

Given, Mass of methanol = 128 g

Molar mass of methanol = 32.04 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{128\ g}{32.04\ g/mol}

Moles\ of\ methanol = 3.995\ mol

Given, Mass of water = 108 g

Molar mass of water = 18.0153 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{108\ g}{18.0153\ g/mol}

Moles\ of\ water= 5.995\ mol

So, according to definition of mole fraction:

Mole\ fraction\ of\ methanol=\frac {n_{methanol}}{n_{methanol}+n_{water}}

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5 0
1 year ago
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DanielleElmas [232]

Answer:

\boxed{ \text{8.40 g}} 

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After a second half-life, half of that amount (25 %) will remain, and so on.  

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      0               0                          1

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1 year ago
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Back to TLC

Original content © University of Colorado at Boulder, Department of Chemistry and Biochemistry.
The information on these pages is available for academic use without restriction.
3 0
1 year ago
the half-life of a certain radioactive element is 1250 years. what percent of the atom remains after 7500 years?
Olenka [21]
Maybe 24% not sure try researching it on google
8 0
2 years ago
The standard reduction potentials for two half-cells involving iron are: given below. Fe2+ (aq) + 2e– ® Fe (s) Eο = –0.44 V Fe3+
matrenka [14]

Answer:

Explanation:

Fe⁺² (aq) + 2e⁻ =   Fe (s)   ;   E⁰ =  - .44 V

Fe⁺³ (aq) + e⁻ =  ® Fe²⁺ (aq) ;   E⁰ = + .77 V

Reduction potential of second reaction is more , so it will take place , ie Fe⁺³ will be reduced and Fe will be oxidised .

So reaction in the combined cell will be

2Fe⁺³ + Fe = 3Fe⁺²

cell potential = .77 - ( - .44 )

= 1.21 V .

6 0
2 years ago
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