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timama [110]
2 years ago
5

If 1 mol of a pure triglyceride is hydrolyzed to give 2 mol of RCOOH, 1 mol of R'COOH, and 1 mol of glycerol, which of the follo

wing compounds might be the triglyceride?
CHOC(O)R
A. CHOC(O)R
CHOC(O)R
CH,OC(O)R
B. CHOC(O)R
CH2OC(O)R
CHOC(O)R
C. CHOC(O)R
CHOC(O)R
CHOC(O)R
D. CHOC(O)R
CHOC(O)R

Chemistry
1 answer:
Ilia_Sergeevich [38]2 years ago
8 0

Answer:

The correct option is C.

Note the full question and structure of the moleculesis found in the attachment below.

Explanation:

Triglycerides or triacylglycerols are non-polar, hydrophobic lipid molecules composed of three fatty acids linked by ester bonds to a molecule of glycerol.

The fatty acids linked to the glycerol molecule are denoted by R and may be of the same kind or different. when the R group is the same, the R is attached in all the three positions for ester bonding in the glycerol molecule but when they are different are denoted by R, R' and R'' respectively.

During the hydrolysis of triglycerides, the three fatty acids molecules are obtained as well as a glycerol molecule.

From the question, when 1 mole of the triglyceride is hydrolysed, 2 moles of RCOOH, 1 mole of R'COOH and 1 mole of glycerol is obtained. The triglyceride must then be composed of two fatty acids which are the same denoted by R, and a different fatty acid molecule denoted by R'.

The correct option therefore, is C

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Answer:

Volume at STP = 0.1401 L

Explanation:

We are given:

Vapor pressure of water = 20 torr

Total vapor pressure = 753 torr

Vapor pressure of gas = Total vapor pressure - Vapor pressure of water = 753 torr - 20 torr = 733 torr

Using

PV=nRT

where,

P = pressure of the gas = 733 torr

V = Volume of the gas = 157 mL= 0.157 L

T = Temperature of the gas = 22^oC=[22+273]K=295K

R = Gas constant = 62.3637\text{ L.torr}mol^{-1}K^{-1}

n = number of moles of gas = ?

Putting values in above equation, we get:

733 torr\times 0.157L=n\times 62.3637\text{L.torr}mol^{-1}K^{-1}\times 295K\\\\n=\frac{733\times 0.157}{62.3637\times 295}=0.006255mol

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3 0
2 years ago
a sample of water with a mass of 648.00 kg at 298 K is heated with 87 kh of energy. the specific heat of water is 1 J-1 kg K-1.
Stels [109]

q = mCΔT

The correct specific heat capacity of water is <em>4.187 kJ/(kg.K)</em>.

ΔT = q/mC = 87 kJ/[648.00 kg x 4.187 kJ/(kg.K)] = 87 kJ/(2713 kJ/K) = 0.032 K

Tf = Ti + ΔT = 298 K + 0.032 K = 298.032 K


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2 years ago
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A rigid, 2.50 L bottle contains 0.458 mol He. The pressure of the gas inside the bottle is 1.83 atm. If 0.713 mol Ar is added to
melomori [17]

Answer:The change in temperature of the gas mixture is -68.44 K.

Explanation:

1. Temperature of the bottle when only helium gas was present :T

Pressure inside the container =P= 1.83 atm

Volume of the container = V = 2.50 L

Moles of helium gas = n = 0.458 moles

Using an Ideal gas equation:

PV=nRT

T=\frac{PV}{nR}=\frac{1.83 atm\times 2.50 L}{0.458 mol\times 0.0820 atm L/mol K}=121.81 K

2. Temperature of the bottle when argon gas is added into the container:T'

Pressure inside the container = P' =2.05 atm

Volume of the container = V = 2.50 L

Moles of helium gas = n' = 0.458 mol + 0.713 mol = 1.171 mol

P'V=n'RT'

T'=\frac{P'V}{n'R}=\frac{2.05 atm\times 2.50 L}{1.171 mol\times 0.0820 atm L/mol K}=53.37 K

The change in temperature will be given as:

Final temperature = Initial temperature:T' - T

53.37 k - 121.81 K = -68.44 K

The change in temperature of the gas mixture is -68.44 K.

7 0
2 years ago
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Estimate ΔG°rxn for the following reaction at 449.0 K. CH2O(g) + 2 H2(g) → CH4(g) + H2O(g) ΔH°= -94.9 kJ; ΔS°= -224.2 J/K
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A kinetics experiment is set up to collect the gas that is generated when a sample of chalk, consisting primarily of solid CaCO3
velikii [3]

(D) Decreasing the particle size of the CacO, by grinding it into a fine powder

Explanation:

To produce more gases by increasing the rate of the chemical reaction, if we grind the chalk into powder, this should walk.

The rate at which chemical reactions takes place is a measure of the speed of  the reaction.

Some factors control the rate of chemical reactions. They are:

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The most applicable in this scenario is grinding the chalk into fine powder. This process increases the surface area exposed. Surface area exposed proportionally affects the rate of a reaction.

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Surface area brainly.com/question/9666705

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