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irakobra [83]
2 years ago
11

Study the following unbalanced half-reaction. Which equation represents the balanced half-reaction? H2O2 ---> H2O

Chemistry
2 answers:
MA_775_DIABLO [31]2 years ago
7 0

Answer : The correct option is, 2e^-+2H^++H_2O_2\rightarrow 2H_2O

Explanation :

The given unbalanced reaction is,

H_2O_2\rightarrow H_2O

(1) The right side is lacking oxygen, so we add a water molecule to it :

H_2O_2\rightarrow H_2O+H_2O

or we can write as,

H_2O_2\rightarrow 2H_2O

(2) Now we have introduced more hydrogen, so we need to balance hydrogen on the left side in acidic solution, we get

2H^++H_2O_2\rightarrow 2H_2O

(3) Now all the atoms are balanced but charge is not balanced. We see that the left side there are two positive charge. So, we balance the charge by adding two negative charge on the left side in the reaction, we get

2e^-+2H^++H_2O_2\rightarrow 2H_2O

Therefore, the correct option is, 2e^-+2H^++H_2O_2\rightarrow 2H_2O

Aleonysh [2.5K]2 years ago
5 0
O: 1*2 = 2*1 
<span>H 2 + 2 = 2*2 </span>

<span>answer C hope you get it right</span>
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Convert 3.8 Km/sec to miles/year
weqwewe [10]
We are asked to convert from units of kilometer per second to units of miles per year. To do this, we need a conversion factor which would relate the different units involved. We either multiply or divide this certain value to the original measurement depending on what is asked. From literature, we will find that 1 mile is equal to 1609 meters and 1000 m is equal to 1 kilometer. Also, we will find that 3600 s is equal to 1 hr, 24 hr is equal to 1 day and 365 days is equal to 1 year. We do the conversion as follows:

3.8 km / s ( 1000 m / 1 km ) ( 1 mile / 1609 meters ) ( 3600 s / 1 hr ) ( 24 hr / 1 day ) ( 365 days / 1 year ) = 74479055.3 miles per year
5 0
1 year ago
Enter your answer in the provided box. An industrial chemist introduces 2.0 atm of H2 and 2.0 atm of CO2 into a 1.00−L container
PSYCHO15rus [73]

Answer: 0.0944 gram of H2

Explanation:

Raising the T from 25 C (298 K) to 700 C (973 K) increases the pressure of each gas by:

2.0 atm x (973 K / 298 K) = 6.53 atm

Where

Kc = Kp because the moles of product equals the moles of reactants.

At equilibriuim, the amounts are

P(H2) = 6.53 - x

P(CO2) = 6.53 - x

P(H2O) = x

P(CO) = x

Kc = Kp = .534 = (x)(x) / [(6.53 - x)(6.53 - x)]

Take the square root of each side

(.534)^0.5 = x / (6.53 - x)

x = 0.731 (6.53 - x)

x = 4.77 - 0.731x

1.731x = 4.77

x = 4.77 / 1.731 = 2.76 atm

P(H2) at equilibriuim = 6.53 - 2.76 = 3.77 atm

P(CO2) at equilibrium = 6.53 - 2.76 = 3.77 atm

PV = nRT

n = PV/RT = [(3.77 atm)(1.00 L)] / [(0.08206 L atm/K mol)(973 K)] = 0.0472 mol H2

0.0472 mol H2 x (2.00 g / 1.00 mol) = 0.0944 g

8 0
2 years ago
Convert 3.4 x 10^23 molecules of NaCl to grams
shusha [124]

Answer:

m_{NaCl}=33g

Explanation:

Hello,

In this case, in order to compute the grams of sodium chloride starting by the molecules, the first step is to compute the moles contained in the given amount of molecules by using the Avogadro's number:

n_{NaCl}=3.4x10^{23}molecules*\frac{1mol}{6.022x10^{23}molecules} =0.56mol

Then, by using the molar mass of sodium chloride (58.45 g/mol) we can directly compute the grams:

m_{NaCl}=0.56mol*\frac{58.45g}{1mol} \\\\m_{NaCl}=33g

Regards.

7 0
2 years ago
An airplane cabin is pressurized to 5.80x10^2.What is the pressure inside the cabin in atmospheres?
joja [24]

Answer:

Explanation:

An airplane cabin is pressurized to 570 mmhg. what is the pressure inside the cabin in atmospheres? a commercial jet takes off from earth's surface and enters the stratosphere

6 0
1 year ago
he first-order rate constant for the gas-phase decomposition of dimethyl ether, (CH3)2O → CH4 + H2 + CO is 3.2 ✕ 10−4 s−1 at 450
seropon [69]

Answer:

0.290 atm is the pressure of the system after 7.7min

Explanation:

The general first-order rate constant is:

ln [A] = -kt + ln [A]₀

<em>Where [A] is concentration of A in time t,</em>

<em>K is rate constant, 3.2x10⁻⁴s⁻¹</em>

<em>[A]₀ is initial concentration = 0.336atm.</em>

<em />

7.7 min are:

7.7min * (60s / 1min) = 462s

Solving:

ln [A] = -kt + ln [A]₀

ln [A] = -<em>3.2x10⁻⁴s⁻¹*462s</em> + ln [0.336atm]

ln [A] = -1.238

[A] =

<h3>0.290 atm is the pressure of the system after 7.7min</h3>

<em />

6 0
2 years ago
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