6,02×10²³ -------------- 18g
3,55×10²² -------------- x
Answer:
H2 P4 O1. Explanation: In order to calculate the Empirical formula , we will assume that we have started with 10 g of the compound.
Explanation:
Answer :Solid in bottle a is ionic, solid in bottle b is molecular and solid in bottle c is ionic.
Explanation :
Ionic compound is formed when a metal atom donates one or more electrons to a non metal. This results in the formation of a cation ( a positive ion) and an anion ( a negative ion). These ions are bonded to each other by electrostatic attraction.
The intermolecular forces in case of a an ionic compound are very strong.
The melting point of a substance depends on how strongly the molecules are attracted to each other. Stronger the forces, higher is the melting point.
Therefore ionic compounds always have very high melting points.
On the other hand, covalent compounds have weak intermolecular forces. Therefore they have low melting points.
Based on above discussion, we can classify the given compounds as follows.
a) Solid in bottle a is Ionic as it has high melting point.
b) Solid in bottle b is molecular as it has low melting point.
c) Solid in bottle c is Ionic as it has high melting point.
In collecting the precipitate, it is inappropriate to heat <span>the reacted mixture and evaporate off the water because it is possible that the mixture contains other substances that precipitates as well when the mixture is being heated so you will not be able to collect what you want.</span>
The basis of finding the answer to this problem is to know the electronic configuration of Fluorine. That would be: <span>[He] 2s</span>²<span> 2p</span>⁵. The valence electrons, which are the outermost electrons of the atom, are the ones that participate in bonding. <em>Since the highest orbital for F is 2p, that means the highest energy occupied would be 2.</em>
