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Papessa [141]
2 years ago
5

Tracie measured 87.47 mg of cholesterol in 0.03 mL of blood. What is the density of this mixture in g/mL?

Chemistry
1 answer:
Lelu [443]2 years ago
5 0

We can use a simple equation to solve this problem.


d = m/v


Where d is the density, m is the mass and v is the volume.


d = ?

m = 87.47 mg = 87.47 x 10⁻³ g

v = 0.03 mL


By applying the equation,

  d = 87.47 x 10⁻³ g / 0.03 mL

  d = 2.92 g/mL



Hence, the density of the mixture is 2.92 g/mL.


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This problem handles<em> boiling-point elevation</em>, which means we will use the formula:

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Knowing that benzene's boiling point is 80.1°C, we <u>solve for m</u>:

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80.23 - 80.1 = 2.64 * m

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We use the definition of molality to <u>calculate the moles of azulene</u>:

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2 years ago
f 23.6 mL of 0.200 M NaOH is required to neutralize 10.00 mL of a H3PO4 solution , what is the concentration of the phosphoric a
Eduardwww [97]

Answer:

Explanation:

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= 0.00472mole

let x be the no of mole of H3PO4 required of  0.00472mole of NaOH

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cross multiply

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