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Reika [66]
2 years ago
15

Calculate the molality of 2.0 M MgCl2 solution. The density of the solution is 1.127 g/mL. (The molar mass of MgCl2 = 95.211 g/m

ol and the molar mass of H2O is 18.02 g/mol.)
Chemistry
2 answers:
Elan Coil [88]2 years ago
8 0

The answer is 2.135 mol/Kg

Given that molarity is 2M, that is, 2 moles in 1 liter of solution.

Density of solution is 1.127 g/ml

Volume of solution is 1L or 1000 ml

mass of solution (m) = density × volume

m₁ = density × volume = 1.127 × 1000 = 1127 g

mass of solute, m₂ = number of moles × molar mass

m₂ = 2 × 95.211

m₂ = 190.422 g

mass of solvent = m₁ - m₂

= 1127 - 190.422

= 936.578 g

= 0.9366 Kg

molality = number of moles of solute / mass of solvent (in kg)

= 2 / 0.9366

= 2.135 mol/Kg

denis23 [38]2 years ago
4 0
The answer is 2.135 mol/Kg
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The final volume is 39.5 L = 0.0395 m³

Explanation:

Step 1: Data given

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P1*V1 = P2*V2

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1.50 *10^6 Pa * 25 L = 0.950 *10^6 Pa * V2

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If 15.6 g of hydrate are heated and only 11.7 g of anhydrous salt remain, calculate the % of water lost.
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Answer:

Percent loss of water = 25%

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