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allsm [11]
2 years ago
8

A poundal is the force required to accelerate a mass of 1 lbm at a rate of 1 ft/s2, and a slug is the mass of an object that wil

l accelerate at a rate of 1 ft/s2 when subjected to a force of 1 lbf.
(
a. Calculate the mass is slugs and the weight in poundals of a 175 lbm man (i) on earth and (ii) on the moon, where the acceleration of gravity is one-sixth of its value on earth.
(
b. A force of 355 poundals is exerted on a 25.0-slug object. At what rate (m/s2) does the object accelerate?
Chemistry
1 answer:
Darya [45]2 years ago
8 0
Remember the formula as per the second Law of Newton: F = m*a

And also remember that the weight is the force with which the mass is attracted by the planet (or satellite in the case of the moon).

With that information you can answer the questions:

a) Weight = F = m*a

m = 175 slugs = 175 lbm

i) Earth

a = 32.17 ft/s^2

Weight on Earth = 175 lbm * 32.17 ft / s^2 = 5,629.75 poundal

ii) Moon

a = [1/6] 32.17 ft/s^2

Weight on the Moon = [1/6]*5,629.75 poundal = 938.29 poundal

b) Force = 355 poundal
m = 25.0 slug

a in m/s^2 = ?

First calculate the force in ft/s^2

F = m*a => a = F/m = 355 poundal / 25.0 slug = 14.2 ft/s^2

Conversion:

14.2 ft / s^2 * [ 0.3048 m/ft] = 4.32816 m/s^2

Answer: 4.33 m/s^2


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tigry1 [53]

Electrolytes conduct electricity because they produce + and – ions in water 
C6H12O6 and CH3CH2OH organic no ions
C6H12O6 and HCl sugar and hydrochloric acid 
NaOH and HCl yields Na+1 ion and Cl-1 ion to conduct electricity
NaOH and CH3CH2OH

Hope this helps. :)

8 0
2 years ago
Read 2 more answers
For each pair of gases, select the one that most likely has the highest rate of effusion. Use the periodic table if necessary. O
madreJ [45]

According to Graham's law, the rate of effusion of a gas is inversely proportional to square root of its molecular weight.

This can be represented as follows.

Rate of effusion ∝  1/√M

Therefore to find which gas has highest rate of effusion, we will find out the molar masses of the given compounds. The gas that is lighter in weight would have highest rate of effusion.

1) Molar mass of oxygen (O₂) is 32 g and that of H₂ is 2.01 g . Therefore H₂ would have highest rate of effusion

2) Molar mass of methane is 16.05 [12.01 + 4 (1.01)] g and that of CCl₄ [ 12 + 4(35.45) ] is 154 g. Therefore methane will have highest rate of effusion

3) Molar mass of N₂ is 28 g and molar mass of NH₃ is [ 14 + 3(3.01) ] = 17.03 g.

Therefore NH₃ will have highest rate of effusion.

4) Molar mass of F₂ is 38 g and that of Cl₂ is 71 g. Therefore F₂ will have highest rate of effusion


7 0
2 years ago
Read 2 more answers
You have 125 g of a certain seasoning and are told that it contains 62.0 g of salt. what is the percentage of salt by mass in th
r-ruslan [8.4K]
62.0g/125g= 0.496 x 100 = 49.6%
4 0
2 years ago
0.9775 grams of an unknown compound is dissolved in 50.0 ml of water. Initially the water temperature is 22.3 degrees Celsius. A
elena-14-01-66 [18.8K]

Answer:

The enthlapy of solution is -55.23 kJ/mol.

Explanation:

Mass of water = m

Density of water = 1 g/mL

Volume of water = 50.0 mL

m = Density of water × Volume of water = 1 g/mL × 50.0 mL=50.0 g

Change in temperature of the water ,ΔT= 27.0°C - 22.3°C = 4.7°C

Heat capacity of water,c =4.186 J/g°C

Heat gained by the water when an unknown compound is dissolved be Q

Q= mcΔT

Q=50.0 g\times 4.186 J/g^oC\times 4.7^oC=983.71 J

heat released when 0.9775 grams of an unknown compound is dissolved in water will be same as that heat gained by water.

Q'=-Q

Q'= -983.71 J =-0.98371 kJ

Moles of unknown compound = \frac{0.9975 g}{56 g/mol}=0.01781 mol

The enthlapy of solution :

\frac{Q'}{moles}

=\frac{-0.98371 kJ}{0.01781 mol}=-55.23 kJ/mol

The enthlapy of solution is -55.23 kJ/mol.

8 0
2 years ago
Which isolated gaseous atom has a total of five electrons occupying spherically shaped orbitals?
Andre45 [30]
Let's find the electron configuration of each atom


Atom      atomic number                electron configuration

Bo            5                                    1s2 2s2 2p
F              9                                    1s2 2s2 2p5 
Na          11                                    1s2 s2 2p6 3s
K            19                                    1s2 2s2 2p6 3s2 3p6 4s      


The spherically shaped orbitals are the s orbitals.



You can se in the table that I wrote above that sodium has 2 electrons at 1s, 2 electrons at 2s and 1 electron at 3s orbitals, that is a total of five electrons at s (spherically shaped orbtials).



So the answer is the option A) sodium.
3 0
2 years ago
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