Electrolytes conduct electricity because they produce + and – ions in water
C6H12O6 and CH3CH2OH organic no ions
C6H12O6 and HCl sugar and hydrochloric acid
NaOH and HCl yields Na+1 ion and Cl-1 ion to conduct electricity
NaOH and CH3CH2OH
Hope this helps. :)
According to Graham's law, the rate of effusion of a gas is inversely proportional to square root of its molecular weight.
This can be represented as follows.
Rate of effusion ∝ 1/√M
Therefore to find which gas has highest rate of effusion, we will find out the molar masses of the given compounds. The gas that is lighter in weight would have highest rate of effusion.
1) Molar mass of oxygen (O₂) is 32 g and that of H₂ is 2.01 g . Therefore H₂ would have highest rate of effusion
2) Molar mass of methane is 16.05 [12.01 + 4 (1.01)] g and that of CCl₄ [ 12 + 4(35.45) ] is 154 g. Therefore methane will have highest rate of effusion
3) Molar mass of N₂ is 28 g and molar mass of NH₃ is [ 14 + 3(3.01) ] = 17.03 g.
Therefore NH₃ will have highest rate of effusion.
4) Molar mass of F₂ is 38 g and that of Cl₂ is 71 g. Therefore F₂ will have highest rate of effusion
Answer:
The enthlapy of solution is -55.23 kJ/mol.
Explanation:
Mass of water = m
Density of water = 1 g/mL
Volume of water = 50.0 mL
m = Density of water × Volume of water = 1 g/mL × 50.0 mL=50.0 g
Change in temperature of the water ,ΔT= 27.0°C - 22.3°C = 4.7°C
Heat capacity of water,c =4.186 J/g°C
Heat gained by the water when an unknown compound is dissolved be Q
Q= mcΔT

heat released when 0.9775 grams of an unknown compound is dissolved in water will be same as that heat gained by water.
Q'=-Q
Q'= -983.71 J =-0.98371 kJ
Moles of unknown compound = 
The enthlapy of solution :


The enthlapy of solution is -55.23 kJ/mol.
Let's find the electron configuration of each atom
Atom atomic number electron configuration
Bo 5 1s2 2s2 2p
F 9 1s2 2s2 2p5
Na 11 1s2 s2 2p6 3s
K 19 1s2 2s2 2p6 3s2 3p6 4s
The spherically shaped orbitals are the s orbitals.
You can se in the table that I wrote above that sodium has 2 electrons at 1s, 2 electrons at 2s and 1 electron at 3s orbitals, that is a total of five electrons at s (spherically shaped orbtials).
So the answer is the option A) sodium.