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MaRussiya [10]
2 years ago
15

Which sentences describe alpha particles? Check all that apply 1. Alpha particles consist of two protons and two neutrons 2. Alp

ha particles consist of a negatively charged electron emitted by a nucleus 3. Alpha particles are produced during alpha decay 4. Alpha particles are produced during beta decay 5. Alpha particles release energy.
answers: 1,3,5 on ed-genuity ...good luck!!
Chemistry
2 answers:
-BARSIC- [3]2 years ago
5 0

<u>Answer:</u> The correct answer are Option 1, Option 3 and Option 5.

<u>Explanation:</u>

Alpha particles are released when a nucleus undergoes alpha decay process. The alpha particle released carries a charge of +2 units and has a mass of 4 units.

The charge of this particle will determine the number of protons present in this particle which are 2 and the mass will determine the number of neutrons in this particle.

Number of neutrons = Mass number - Number of protons

Number of neutrons = 4 - 2 = 2

This particle also releases energy with itself.

Hence, the correct answer are Option 1, Option 3 and Option 5.

Masja [62]2 years ago
4 0

thanks for the answers ッ. (btw they’re on the bottom of the question if anyone doesn’t see it.

You might be interested in
) The only noble gas without eight valence electrons is __________. A) Ar B) Ne C) Kr D) He E) All noble gases have eight valenc
nadya68 [22]

Answer:

D) He

Explanation:

Helium is in the first period. It only has 1 valence electron so it's very reactive. (This could be completely wrong and I'm sorry if it is.)

6 0
2 years ago
How many moles of tungsten (W,183.85 g/mol) are in 415 grams of tungsten?
ozzi
2.25739773716275. I used a calculator during class today to get this answer, and I am pretty sure it is right, hope it helps. 
8 0
2 years ago
Read 2 more answers
4. The stockroom contains 1.0 M NaAc (Sodium Acetate), 1.0 M HAc (acetic Acid), distilled water and strong acids and bases. You
Elina [12.6K]

Answer:

Concentrations of HAc and NaAc you need are 0.122M

Explanation:

pKa of acetic acid is 4.75, that means when amount of sodium acetate and acetic acid is the same, pH will be 4.75

Thus, you know [NaAc]i = [HAc]i

Now, using H-H equation, when pH = 3.75:

3.75 = 4.75 + log [NaAc] / [HAc]

0.1 = [NaAc] / [HAc]

10 [NaAc] = [HAc]

Thus, after the reaction  [HAc] must be ten times,  [NaAc].

Based in the reaction of NaAc with HCl

NaAc + HCl → HAc + NaCl

Moles of HCl added are:

1mL = 0.001L * (10mol /L) = 0.01 moles HCl.

That means moles of both compounds after the reaction are:

<em>[NaAc] = [NaAc]i - 0.01 mol </em>

[HAc] = [HAc]i + 0.01

Replacing these equations with the information you know:

[NaAc] = [NaAc]i - 0.01 mol

10[NaAc] = [NaAc]i + 0.01

Subtracting both equations:

9[NaAc] = 0.02mol

[NaAc] = 0.0022 moles.

Replacing in <em>[NaAc] = [NaAc]i - 0.01 mol </em>

0.0022mol = [NaAc]i - 0.01 mol

0.0122mol = [NaAc]i = [HAc]i

These moles in 100.00mL = 0.1000L:

[NaAc]i = [HAc]i = 0.0122mol / 0.100L =

0.122M

Thus, <em>concentrations of HAc and NaAc you need are 0.122M</em>

<em />

To create this buffer, you need to pipette 12.2mL of both 1.0M NaAc and 1.0M HAc and dilute this mixture to 100.0mL

4 0
1 year ago
Naturally occurring iodine has an atomic mass of 126.9045 amu. A 12.3849-g sample of iodine is accidentally contaminated with 1.
Oliga [24]

Answer:

127.0665 amu

Explanation:

Firstly, to answer the question correctly, we need to access the percentage compositions of the iodine and the contaminant iodine. We can do this by placing their individual masses over the total and multiplying by 100%.

We do this as follows. Since the mass of the contaminant iodine is 1.00070g, the mass of the 129I in that particular sample will be 12.3849 - 1.00070 = 11.3842g

The percentage abundances is as follows:

Synthetic radioisotope % = 1.0007/12.3849 * 100% = 8.1%

Since there are only two constituents, the percentage abundance of the 129I would be 100 - 8.1 = 91.9%

Now, we can use these percentages to get the apparent atomic mass. We get this by multiplying the percentage abundance’s by the atomic masses of both and adding together.

That is :

[8.1/100 * 128.9050] + [91.9/100 * 126.9045] = 10.441305 + 116.6252355 = 127.0665 amu

6 0
1 year ago
Write chemical equations and corresponding equilibrium expressions for each of the two ionization steps of carbonic acid. Part A
lesantik [10]

<u>Answer:</u> The chemical equations and equilibrium constant expression for each ionization steps is written below.

<u>Explanation:</u>

The chemical formula of carbonic acid is H_2CO_3. It is a diprotic weak acid which means that it will release two hydrogen ions when dissolved in water

The chemical equation for the first dissociation of carbonic acid follows:

               H_2CO_3(aq.)\rightleftharpoons H^+(aq.)+HCO_3^-(aq.)

The expression of first equilibrium constant equation follows:

Ka_1=\frac{[H^+][HCO_3^{-}]}{[H_2CO_3]}

The chemical equation for the second dissociation of carbonic acid follows:

               HCO_3^-(aq.)\rightarrow H^+(aq.)+CO_3^{2-}(aq.)

The expression of second equilibrium constant equation follows:

Ka_2=\frac{[H^+][CO_3^{2-}]}{[HCO_3^-]}

Hence, the chemical equations and equilibrium constant expression for each ionization steps is written above.

6 0
2 years ago
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