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2 years ago

What is it with the name Sara these days!? XD

Chemistry

1 answer:

Komok [63]2 years ago

7 0

66 mph

Explanation:

Average speed is the rate of change of distance with time:

Average speed = $\frac{Distance }{time}$

Given parameters:

Starting point = 88mile marker

End of journey = 121mile marker

time = 30minutes = 0.5hr(60min = 1hr)

Solution:

The distance covered in this journey:

Distance = End of journey - starting point = 121 mile - 88 mile = 33mile

Average speed = $\frac{33miles}{0.5hr}$

= 66mph

The average speed of Sara's mum is 66mph

Learn more:

Average speed brainly.com/question/8893949

#learnwithBrainly

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A blacksmith making a tool heats 525 grams of steel to 1230°C. After hammering the steel, she places it into a bucket of water t

Simora [160]

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6 0

2 years ago

Write the electron configurations for the following ions:

Ket [755]

Answer:

Co²⁺ : 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁷

Sn²⁺ : 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰

Zr⁴⁺ : 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶

Ag⁺ : 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 4d¹⁰

S²⁻ : 1s² 2s² 2p⁶ 3s² 3p⁶

Explanation:

Cobalt (Co): atomic number 27

The electronic configuration of Co in ground state:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁷

The electronic configuration of Co in +2 oxidation state (Co²⁺) :

1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁷

Tin (Sn): atomic number 50

The electronic configuration of Sn in ground state:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p²

The electronic configuration of Sn in +2 oxidation state (Sn²⁺) :

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰

Zirconium (Zr): atomic number 40

The electronic configuration of Zr in ground state:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d²

The electronic configuration of Zr in +4 oxidation state (Zr⁴⁺) :

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶

Silver (Ag): atomic number 47

The electronic configuration of Ag in ground state:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s¹ 4d¹⁰

The electronic configuration of Ag in +1 oxidation state (Ag⁺) :

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 4d¹⁰

Sulphur (S): atomic number 16

The electronic configuration of S in ground state:

1s² 2s² 2p⁶ 3s² 3p⁴

The electronic configuration of S in -2 oxidation state (S²⁻) :

1s² 2s² 2p⁶ 3s² 3p⁶

8 0

2 years ago

Read 2 more answers

A 0.500 g sample of tin (Sn) is reacted with oxygen to give 0.534 g of product. What is the empirical formula of the oxide?

REY [17]

Answer:

$Sn_2O$

Explanation:

Hello,

In this case, given that the mass of the product is 0.534 g, we can infer that the percent composition of tin is:

$\%Sn=\frac{0.500g}{0.534g}*100\%\\ \\\%Sn=93.6\%$

Therefore, the percent composition of oxygen is 6.4% for a 100% in total. Thus, with such percents we compute the moles of each element in the oxide:

$n_{Sn}=93.6gSn*\frac{1molSn}{118.8gSn} =0.788molSn\\\\n_O=6.4gO*\frac{1molO}{16gO}=0.4molO$

In such a way, for finding the smallest whole number we divide the moles of both tin and oxygen by the moles of oxygen as the smallest moles:

$Sn:\frac{0.788}{0.4}=2\\ \\O:\frac{0.4}{0.4}=1$

Therefore, the empirical formula is:

$Sn_2O$

Best regards.

8 0

2 years ago

Arsenic produces a blue flame when heated. Calcium produces an orange-red flame. Which of these best explains why this differenc

MrMuchimi

Flame colors are produced from the movement of the electrons in the metal ions present in the compounds. When you heat it, the electrons gain energy and can jump into any of the empty orbitals at higher levels Each of these jumps involves a specific amount of energy being released as light energy, and each corresponds to a particular color. As a result of all these jumps, a spectrum of colored lines will be produced. The color you see will be a combination of all these individual colors.

6 0

2 years ago

The reaction of 0.779 g K with O2 forms 1.417 g potassium superoxide, a substance used in self-contained breathing devices. Dete

zhannawk [14.2K]

First we need to find the number of moles of both K and O reacted
K - 0.779 g / 39 g/mol
= 0.02 mol
the mass of O₂ reacted = 1.417 g - 0.779 g = 0.638 g
O₂ moles = 0.638 g / 32 g/mol
= 0.02 mol
the number of both K and O₂ moles reacted are equal
therefore stoichiometry of K to O₂ reacted are 1:1
then the formula of potassium superoxide is KO₂

3 0

2 years ago