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2 years ago

According to the College Undergraduate Stress Scale, _____ is rated as more stressful than is flunking a class.

1 answer:

5 0

The answer is flunking a class. Flunking a class during college years is the most stressful item in the College Undergraduate Stress Scale (CUSS). Flunking a class means failing it, which results to more stress, it will make you take it again, but it depends on that subject’s availability. You’re chances of graduating early may be hindered because of a flunked class. There is nothing more stressful than flunking a class.

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For each pair below, select the sample that contains the largest number of moles. Pair A 2.50 g O2 2.50 g N2

raketka [301]

Answer:

Explanation:

Pair 2.50g of O₂ and 2.50g of N₂

The atoms sample with the largest number of moles since the masses are the same would be the one with lowest molar mass according the the equation below:

Number of moles = $\frac{mass }{molarmass}$

Atomic mass of O = 16g and N = 14g

Molar mass of O₂ = 16 x 2 = 32gmol⁻¹

Molar mass of N₂ = 14 x 2 = 28gmol⁻¹

Number of moles of O₂ = $\frac{2.5}{32}$ = 0.078mole

Number of moles of N₂ = $\frac{2.5}{28}$ = 0.089mole

We see that N₂ has the largest number of moles

4 0

2 years ago

Read 2 more answers

Calculate the maximum concentration (in m) of silver ions (ag+) in a solution that contains 0.025 m of co32-. the ksp of ag2co3

Helen [10]

Equilibrium equation is

Ag2CO3(s) <---> 2 Ag+(aq) + CO32-(aq) 

From the reaction equation above, the formula for Ksp: 

Ksp = [Ag+]^2 [CO32-] = 8.1 x 10^-12 
You know [CO32-], so you can solve for [Ag+] as: 
(8.1 x 10^-12) = [Ag+]^2 (0.025) 
[Ag+]^2 = 3.24 x 10^-10 
[Ag+] = 1.8 x 10^-5 M

5 0

2 years ago

If a 60-g object has a volume of 30 cm3, what is its density? 2 g/cm3 0.5 cm3/g 1800 g * cm3 none of the above

jasenka [17]

Answer : The density of an object is, $2g/cm^3$

Solution : Given,

Mass of an object = 60 g

Volume of an object = $30cm^3$

Formula used :

$\text{Density of an object}=\frac{\text{Mass of an object}}{\text{Volume of an object}}$

Now put all the given values in this formula, we get the density of an object.

$\text{Density of an object}=\frac{60g}{30cm^3}=2g/cm^3$

Therefore, the density of an object is, $2g/cm^3$

6 0

2 years ago

There is water on the pan of the scale as you measure the mass of an object. If you were to ignore the water, what would be the

mihalych1998 [28]

Remember that density refers to the "mass per unit volume" of an object.

So, if an object had a mass of 100 grams and a volume of 100 milliliters, the density would be 100 grams / 100 ml.

In the question, water on the surface of the scale would add weight, so the mass of the object that you're weighing would appear to be heavier than it really is. If that happens, you'll incorrectly assume that the density is GREATER than it really is

As an example, suppose that there was 5 ml of water on the surface of the scale. Water has a density of 1 gram per milliliter (1 g/ml) so the water would add 5 grams to the object's weight. If we use the example above, the mass of the object would seem to be 105 grams, rather than 100 grams. So, you would calculate:

density = mass / volume
density = 105 grams / 100 ml
density = 1.05 g/ml

The effect on density would be that it would erroneously appear to be greater

Hope this helps!

Good luck

6 0

2 years ago

In each row, check the box under the compound that can reasonably be expected to be more acidic in aqueous solution, e.g. have t

vredina [299]

Answer:

$HCH_{3}SO_{2}$

$H_{3}PO_{3}$

$HClO_{2}$

Explanation:

Every acid (HA) tends to disolve into proton ( $H^{+}$ ) and anion ( $A^{-}$ ) in aqueous solution. Acid strength can be determined by measuring this tendency to separate into proton an anion. Strength of an acid can be quantified by its acid dissociation value - Ka. A strong acid will have a tendency to easily release proton and will have larger Ka value and smaller logarithmic value (pKa = - logKa) similar to calculating pH of the solution. So the easiest way to resolve this issue is by looking for Ka or pKa value of the acid (This table may be useful in more complex tasks and is attached below). However, stronger acid can be determined elsehow.

a) Carbon is element 14 with 4 valent electrons and sulfur is element 16 with 6 valence electrons. Thus, sulfur has stronger electronegativity (tendency to attract bonded electrons towards itself). This means that sulfur will hold oxygen tighter to itself so the hydrogen bond to it can be more easily separated from it. $HCH_{3}SO_{2}$ is more acidic in aqueous solution.

b) In $H_{3}PO_{4}$ , phosphorus holds one double bond with oxygen and three OH group equally. To show an acidic tendency, phosphorus would need to let go one hydrogen out of one of OH groups. In $H_{3}PO_{3}$ , phosporus holds two double bong with oxygen, one OH and one hydrogen, all single and lonely, ready to leave phosphorus and show acidic characteristics in aqueous solution. Thus, $H_{3}PO_{3}$ is more acidic compound.

C) In all Cl acids, the electron density is placed around Cl so the more oxygen around Cl, the more acidic will be the chemical. This is comparable to an oxidation state - the bigger oxidation state, the stronger acid will be:

$HClO_{4} ^{+7} >HClO_{3}^{+5} >HClO_{2}^{+3} >HClO_{}^{+1}$

$HClO_{2}$ can reasonably be expected to be more acidic in aqueous solution.

4 0

2 years ago