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Igoryamba
2 years ago
8

Nucleophilicity is a kinetic property. A higher nucleophilicity indicates that the nucleophile will easily donate its electrons

to the electrophile and that the reaction will occur at the faster rate. The reaction rate also depends on the nature of the electrophile and solvent. Rank the following reactions from fastest to slowest based on the nucleophilicity of the nucleophile.
a. CH3NH- + CH3--Br → CH3NHCH3 + Br-
b. (CH3)2N- + CH3--Br → (CH3)2NCH3 + Br-
c. H2N- + CH3--Br → CH3NH2 +Br-
Chemistry
1 answer:
lord [1]2 years ago
3 0

The rate constant (K) is related to activation energy (Ea), frequency factor (A) and temperature (T) in Kelvin by the equation

R = molar gas constant

K = A(e^(-Ea/RT))

Taking natural log of both sides

In K = In A - (Ea/RT)

In K = (-Ea/R)(1/T) + In A

Comparing this to the equation of a straight line; y = mx + c

y = In K, slope, m = (-Ea/R), x = (1/T) and intercept, c = In A

a) From the question, m = (-Ea/R) = -1.10 × (10^4) K

(-Ea/R) = -1.10 × (10^4) = -11000

R = 8.314 J/K.mol

Ea = -11000 × 8.314 = 91454 J/mol = 91.454 KJ/mol

b) c = In A = 33.5

A = e^33.5 = (3.54 × (10^14))/s

c) K = A(e^(-Ea/RT))

A = (3.54 × (10^14))/s, Ea = 91454 J/mol, T = 25°C = 298.15 K, R = 8.314 J/K.mol

K = (3.54 × (10^14))(e^(-91454/(8.314×298.15))) = 0.0336/s

QED!

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Answer: <span>9330 j/mol
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K= 3/2 * kB * T
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8 0
1 year ago
Identify the Lewis acids and Lewis bases in the following reactions:
postnew [5]

Answer: 1. H^++OH^-\rightarrow H_2O  Lewis acid : H^+, Lewis base : OH^-

2. Cl^-+BCl_3\rightarrow BCl_4^- Lewis acid : BCl_3, Lewis base : Cl^-

3. K^++6H_2O\rightarrow K(H_2O)_6 Lewis acid : K^+, Lewis base : H_2O

Explanation:

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

1. H^++OH^-\rightarrow H_2O

As H^+ gained electrons to complete its octet. Thus it acts as lewis acid.OH^- acts as lewis base as it donates lone pair of electrons to electron deficient specie H^+.

2. Cl^-+BCl_3\rightarrow BCl_4^-

As BCl_3 is short of two electrons to complete its octet. Thus it acts as lewis acid. Cl^- acts as lewis base as it donates lone pair of electrons to electron deficient specie BCl_3.

3. K^++6H_2O\rightarrow K(H_2O)_6

As K^+ is short of electrons to complete its octet. Thus it acts as lewis acid. H_2O acts as lewis base as it donates lone pair of electrons to electron deficient specie K^+.

8 0
2 years ago
Methane (CH4) reacts with excess oxygen gas (O2) to produce carbon dioxide (CO2) and water (H2O). What is the percent yield of c
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(hope this helps)
4 0
1 year ago
Read 2 more answers
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Oliga [24]

You add the both equations, remove the molecules that may be found in the same time at the right and left of the reaction and balance the equation. Doing so you will get:

6 CaC₂ (s) + 16 H₂O (g) + 3 CO₂ (g) → 5 CH₂=CH-COOH (g) + 6 Ca(OH)₂ (s)

7 0
1 year ago
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Calculate the pka of hypochlorous acid. The ph of a 0.015 m solution of hypochlorous acid has a ph of 4.64.
o-na [289]

Answer:

  • pKa = 7.46

Explanation:

<u>1) Data:</u>

a) Hypochlorous acid = HClO

b) [HClO} = 0.015

c) pH = 4.64

d) pKa = ?

<u>2) Strategy:</u>

With the pH calculate [H₃O⁺], then use the equilibrium equation to calculate the equilibrium constant, Ka, and finally calculate pKa from the definition.

<u>3) Solution:</u>

a) pH

  • pH = - log [H₃O⁺]

  • 4.64 = - log [H₃O⁺]

  • [H_3O^+]= 10^{-4.64} = 2.29.10^{-5}

b) Equilibrium equation: HClO (aq) ⇄ ClO⁻ (aq) + H₃O⁺ (aq)

c) Equilibrium constant: Ka =  [ClO⁻] [H₃O⁺] / [HClO]

d) From the stoichiometry: [CLO⁻] = [H₃O⁺] = 2.29 × 10 ⁻⁵ M

e) By substitution: Ka = (2.29 × 10 ⁻⁵ M)² / 0.015M = 3.50 × 10⁻⁸ M

f) By definition: pKa = - log Ka = - log (3.50 × 10 ⁻⁸) = 7.46

5 0
2 years ago
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