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lianna [129]
2 years ago
6

Type the correct answer in the box. Express your answer to three significant figures.

Chemistry
2 answers:
VladimirAG [237]2 years ago
7 0

<u>Given:</u>

Mass of calcium nitrate (Ca(NO3)2) = 96.1 g

<u>To determine:</u>

Theoretical yield of calcium phosphate, Ca3(PO4)2

<u>Explanation:</u>

Balanced Chemical reaction-

3Ca(NO3)2 + 2Na3PO4 → 6NaNO3 + Ca3(PO4)2

Based on the reaction stoichiometry:

3 moles of Ca(NO3)2 produces 1 mole of Ca3(PO4)2

Now,

Given mass of Ca(NO3)2 =  96.1 g

Molar mass of Ca(NO3)2 =  164 g/mol

# moles of ca(NO3)2 = 96.1/164 = 0.5859 moles

Therefore, # moles of Ca3(PO4)2 produced = 0.0589 * 1/3 = 0.0196 moles

Molar mass of Ca3(PO4)2 = 310 g/mol

Mass of Ca3(PO4)2 produced = 0.0196 * 310 = 6.076 g

Ans: Theoretical yield of Ca3(PO4)2 = 6.08 g



ipn [44]2 years ago
6 0

Answer: The mass of calcium phosphate the reaction can produce is  59.95 g.

Explanation:

3Ca(NO_3)_2+2Na_3PO_4\rightarrow 6NaNO_3+Ca_3(PO_4)_2

Moles of Ca(NO_3)_2=\frac{\text{given Mass of }Ca(NO_3)_2}{\text{Molar Mass of }Ca(NO_3)_2}=\frac{96.1 g}{164.08 g/mol}=0.58 mol

According to reaction:

3 mole of Ca(NO_3)_2 gives 1 mole of Ca_3(PO_4)_2

Then 0.58 moles of Ca(NO_3)_2 will give = \frac{1}{3}\times 0.58 moles of Ca_3(PO_4)_2 that is 0.1933 moles

Mass of Ca_3(PO_4)_2: number of Moles × Molar mass

=0.1933\times 310.18 g/mol=59.95 g

The mass of calcium phosphate the reaction can produce is  59.95 g.

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A rod, X has a positive charge of 8. An otherwise identical rod, Y has a negative charge of 4. The rods are touched together, an
gtnhenbr [62]

Answer:

1.  electrons

2. From "Y" to "X"

Explanation:

1. Electrons move between the rod since the electrons are the only charge carriers which are free to move.

2. The particles move from from "Y" to "X"  since the electrons are the only charge carriers which are free to move. The positive charge on rod x is due to a deficit of electrons while the negative charge on rod Y is due to the excess of electrons. When the rods come together, the electrons move from "Y" to "X" since the electrons are the only charge carriers which are free to move.

4 0
1 year ago
Lithium has an atomic mass of 6.941 amu. Lithium has two common isotopes. The one isotope has a mass of 6.015 amu and a relative
koban [17]

Answer:

The atomic mass of second isotope is 7.016

Explanation:

Given data:

Average Atomic mass of lithium = 6.941 amu

Atomic mass of first isotope = 6.015 amu

Relative abundance of first isotope = 7.49%

Abundance of second isotope = ?

Atomic mass of other isotope = ?

Solution:

Total abundance = 100%

100 - 7.49 = 92.51%

percentage abundance of second isotope = 92.51%

Now we will calculate the mass if second isotope.

Average atomic mass of lithium = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

6.941 = (6.015×7.49)+(x×92.51) /100

6.941 =  45.05235 + (x92.51) / 100

6.941×100 = 45.05235 + (x92.51)

694.1 - 45.05235   = (x92.51)

649.04765 = x 92.51

x = 485.583 /92.51

x = 7.016

The atomic mass of second isotope is 7.016

3 0
2 years ago
Rank the formation of the solutions A, B, and C from the most exothermic to the most endothermic. Rank the enthalpy of solution
Elodia [21]

This is an incomplete question, the table is attached below.

Answer : The correct ranking of the solution from most exothermic to most endothermic will be: A, B and C.

Explanation :

As we know that the intermolecular force of attraction play an important role in the interaction of solute-solute, solute-solvent and solvent solvent solution.

In the solution A, the solute-solute and solvent-solvent interactions are weak. So, their solute-solvent interaction will be strong. That means, the solution will be more exothermic.

In the solution C, the solute-solute and solvent-solvent interactions are strong. So, their solute-solvent interaction will be weak. That means, the solution will be more endothermic.

Thus, the correct ranking of the solution from most exothermic to most endothermic will be: A, B and C.

4 0
2 years ago
Suppose you need 7.0 m of Grade 70 tow chain, which has a diameter of 38" and weighs , 2.16/kgm to tow a car. How would you calc
STatiana [176]

Answer : The mass of 7.0 m chain is, 15.12 kg

Explanation :

As we are given that,

The weight of the chain per unit length = 2.16 kg/m

Now we have to determine the mass of chain for 7.0 m length.

As, the mass of 1 m length of chain = 2.16 kg

So, the mass of 7.0 m length of chain = \frac{7.0m}{1m}\times 2.16kg

                                                                = 15.12 kg

Therefore, the mass of 7.0 m chain is, 15.12 kg

3 0
2 years ago
Paige heated 3.00 g mercury (II) oxide (HgO, 216.59 g/mol) to form mercury (Hg, 200.59 g/mol) and oxygen (O2, 32.00 g/mol). She
stepan [7]

the balanced chemical equation for decomposition of HgO is as follows

2HgO --> 2Hg + O₂

stoichiometry of HgO to O₂ is 2:1

number of HgO moles heated are - 3.00 g / 216.59 g/mol = 0.0139 mol

according to stoichiometry of reaction -

number of O₂ moles formed = 0.0139 mol/ 2 = 0.00695 mol

mass of O₂ to be formed - 0.00695 mol x 32.00 g/mol = 0.2224 g

but the actual yield = 0.195 g

percent yield = actual yield / theoretical yield x 100 %

percent yield = 0.195 g / 0.2224 g x 100 % = 87.7 %

answer is 87.7 %

8 1
2 years ago
Read 2 more answers
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