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Kay [80]
1 year ago
6

500 mL of He at 300 K is heated to 450 K. Find V2

Chemistry
1 answer:
ruslelena [56]1 year ago
8 0

Answer:

V2 = 0.75 L

Explanation:

assumin ideal gas:

  • PV = RTn

∴ T1 = 300K

∴ V1 = 0.500 L

∴ T2 = 450 K

⇒ V2 = ?

assuming P, n constant:

⇒ PV1 = RT1n

⇒ V1/T1 = Rn/P = K..........(1)

⇒ V2/T2 = RN/P = K..........(2)

(1) = (2):

⇒ V1/T1 = V2/T2

⇒ V2 = (V1/T1)T2

⇒ V2 = (0.500 L/300 K)(450 K)

⇒ V2 = 0.75 L

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1 year ago
What is the molar mass of 56.75 g of gas exerting a pressure of 2.87 atm on the walls of a 5.29 l container at 230 k?
laiz [17]
We first need to find the number of moles of gas in the container 
PV = nRT
where;
P - pressure - 2.87 atm x 101 325 Pa/atm = 290 802.75 Pa
V - volume - 5.29 x 10⁻³ m³
n - number of moles
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 230 K
substituting these values in the equation 
290 802.75 Pa x  5.29 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 230 K
n = 0.804 mol
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molar mass of gas = 56.75 g / 0.804 mol 
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1 year ago
Martin is conducting an experiment. His first test gives him a yield of 5.2 grams. His second test gives him a yield of 1.3 gram
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Which term names the metamorphic change to a rock that results mainly from the heat energy of nearby magma? A. local metamorphis
marshall27 [118]
The answer to this question would be: <span>thermal metamorphism
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PLZ HELP ASAP PLATO!!! BRAINLIEST TO WHOEVER ANSWERS CORRECTLY!!!
katen-ka-za [31]

Explanation:

a. 0.0093

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Number of significant figures = 4

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c. 1,000

Number of significant figures = 1

All zeroes used solely for spacing the decimal point are not significant.

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Number of significant figures = 4

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All zero’s after the decimal point are always significant.

e. 670

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f. 0.184

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All zero’s after the decimal point are always significant.

g. 1.30

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All zero’s after the decimal point are always significant.

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