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2 years ago

500 mL of He at 300 K is heated to 450 K. Find V2

Chemistry

1 answer:

ruslelena [56]2 years ago

8 0

Answer:

V2 = 0.75 L

Explanation:

assumin ideal gas:

PV = RTn

∴ T1 = 300K

∴ V1 = 0.500 L

∴ T2 = 450 K

⇒ V2 = ?

assuming P, n constant:

⇒ PV1 = RT1n

⇒ V1/T1 = Rn/P = K..........(1)

⇒ V2/T2 = RN/P = K..........(2)

(1) = (2):

⇒ V1/T1 = V2/T2

⇒ V2 = (V1/T1)T2

⇒ V2 = (0.500 L/300 K)(450 K)

⇒ V2 = 0.75 L

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