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Zepler [3.9K]
2 years ago
7

Using two spring scales, students pull on opposite sides of a dynamic cart at rest. 7 Newtons of force is pulling left and 5 New

tons force is pulling right. Describe the motion of the cart? A) The cart will move to the right. B) The cart will move to the left. C) The cart will not move. D) The cart will move up.
Chemistry
1 answer:
Nadya [2.5K]2 years ago
5 0

Answer is: B) The cart will move to the left.

A newton (N) is the International unit of measure for force.

One newton is the force needed to accelerate one kilogram of mass at the rate of one metre per second squared in direction of the applied force.

The cart will move to the left by the force of 2 newton.

F(cart) = 7 N - 5 N.

F(cart) = 2 N to the left.

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Write the expression for the equilibrium constant Kp for the following reaction.Enclose pressures in parentheses and do NOT writ
maxonik [38]

<u>Answer:</u> The expression for K_p is written below.

<u>Explanation:</u>

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of the products and the reactants each raised to the power their stoichiometric ratios. It is expressed as K_p

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_p is written as:

K_p=\frac{P_{C}^c\times P_{D}^d}{P_{A}^a\times P_{B}^b}

The partial pressure for solids and liquids are taken as 1.

For the given chemical equation:

NH_4HS(s)\rightleftharpoons NH_3(g)+H_2S(g)

The expression for K_p for the following equation is:

K_p=\frac{(P NH_3)\times (P H_2S)}{(P NH_4HS)}

The partial pressure of NH_4HS will be 1 because it is solid.

So, the expression for K_p now becomes:

K_p=\frac{(P NH_3)\times (P H_2S)}{1}

Hence, the expression for K_p is written above.

5 0
2 years ago
What type of chemical reaction is this? Cl2(g) + 2KBr(aq) - 2KCl(aq) + Br2(l)
Sindrei [870]
C. Single-replacement

Chlorine replaces Bromine in KBr.
7 0
2 years ago
If the volume of a container of gas is reduced, what will happen to the pressure inside the container?
blondinia [14]
B).The pressure will not change

8 0
2 years ago
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Categorize the following materials: bronze alloy, mouse growing an ear on its back, porcelain dentures
masha68 [24]
Bronze alloy and porcelain dentures
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Tag all the carbon atoms with pi bonds in this molecule. If there are none, please check the box.
snow_tiger [21]

Answer:

Pi bonds (π bonds) are covalent chemical bonds where two lobes of an orbital involved in the bond overlap with two lobes of the other orbital involved. These orbitals share a nodal plane that passes through the nuclei involved. Are generally weaker than sigma links, because their negatively charged electronic density is further from the positive charge of the atomic nucleus, which requires more energy.

They are frequent components of multiple bonds, as is the molecule indicated in our exercise.

The characteristics that distinguish pi bonds from other kinds of interactions between atomic species are described below, beginning with the fact that this union does not allow the free rotation movement of atoms, such as carbon. For this reason, if there is rotation of the atoms, the bond is broken.

Explanation:

In order to describe the formation of the pi bond, first we must talk about the hybridization process, as this is involved in some important links.

Hybridization is a process where hybrid electronic orbitals are formed; that is, where orbitals of atomic sub-levels s and p can get mixed. This causes the formation of sp, sp2 and sp3 orbitals, which are called hybrids.

In this sense, the formation of pi bonds occurs thanks to the overlapping of a pair of lobes belonging to an atomic orbital over another pair of lobes that are in an orbital that is part of another atom.

This orbital overlap occurs laterally, so the electronic distribution is mostly concentrated above and below the plane formed by the linked atomic nuclei, and causes the pi bonds to be weaker than the sigma bonds.

When talking about the orbital symmetry of this type of junction, it should be mentioned that it is equal to that of the p-type orbitals as long as it is observed through the axis formed by the bond. In addition, these junctions are mostly made up of p orbitals.

Since pi bonds are always accompanied by one or two more links (one sigma or another pi and one sigma), it is relevant to know that the double bond that is formed between two carbon atoms has less bond energy than that corresponding to two Sometimes the sigma link between them.

4 0
2 years ago
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