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harkovskaia [24]
2 years ago
8

An earthquake on the ocean floor produced a giant wave called a tsunami. The tsunami traveled through the ocean and hit a remote

island, causing a lot of damage. Is the water that hit the island the same water that was above the earthquake on the ocean floor?
Chemistry
1 answer:
Svetlanka [38]2 years ago
8 0

Answer:

Yes

Explanation:

What cause an earthquake is when the earth plates shift and if theirs a drop in the tentonic plates a ripple effect like when you drop something in water will occur. The plates shift down the water in which the plate shift down the water will go in that direction due to gravity, but instead of equalizing the water will pick up some speed and velocity and begin to form a wave now. When an tsunami happens you know it coming cause the water moves back cause the water is picking up to much speed and due to cohesion its moves along with the move water and builds up. Creating a massive tidal wave known as tsunamis.

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Equal numbers of moles of He(g), Ar(g), and Ne(g) are placed in a glass vessel at room temperature. If the vessel has a pinhole-
mrs_skeptik [129]

Answer:

VP as function of time => VP(Ar) > VP(Ne) > VP(He).

Explanation:

Effusion rate of the lighter particles will be higher than the heavier particles. That is, the lighter particles will leave the container faster than the heavier particles. Over time, the vapor pressure of the greater number of heavier particles will be higher than the vapor pressure of the lighter particles.

=> VP as function of time => VP(Ar) > VP(Ne) > VP(He).

Review Graham's Law => Effusion Rate ∝ 1/√formula mass.

4 0
2 years ago
A solution of sodium acetate (ch3coona) in water is weakly basic. <br> a. True <br> b. False
guajiro [1.7K]
Hello!

The statement that a solution of sodium acetate (CH₃COONa) is weakly basic is true:

Sodium acetate is the conjugate base of Acetic Acid. When sodium acetate is dissolved in water, it follows the equation that is shown below:

CH₃COONa(s) → CH₃COO⁻(aq) + Na⁺(aq)

Now the Acetate (CH₃COO⁻) ion, has an equilibrium in water to produce hydroxyl (OH⁻) ions and (Acetic Acid CH₃COOH)

CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻

This is a weak equilibrium, and the hydroxyl ions cause the solution to be weakly basic.

Have a nice day!
7 0
2 years ago
Let's say we have 2 Zinc atoms and 2 Sulfur atoms on one side of the equation. According to the Law of Conversation and Mass, ho
Viefleur [7K]

Answer:

Two

Explanation:

The law of conservation of mass states that in an isolated system the mass present is neither destroyed nor created by chemical changes or physical changes.

This tells us that the mass of reactants must be equal to the product mass.

If 1 atom of Zn react with one atoms of sulfur, the product will be 1 molecule of zinc sulfide according to the equation below

Zn(s) + S(s) ⇒ ZnS(s)

therefore two atoms each f zinc and sulfur will product two molecules of Zn sulfide

5 0
1 year ago
4.82 g of an unknown metal is heated to 115.0∘C and then placed in 35 mL of water at 28.7∘C, which then heats up to 34.5∘C. What
nikitadnepr [17]

<u>Answer:</u> The specific heat of metal is 2.34 J/g°C

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 35 mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{35mL}\\\\\text{Mass of water}=(1g/mL\times 35mL)=35g

When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]      ......(1)

where,

q = heat absorbed or released

m_1 = mass of metal = 4.82 g

m_2 = mass of water = 35 g

T_{final} = final temperature = 34.5°C

T_1 = initial temperature of metal = 115°C

T_2 = initial temperature of water = 28.7°C

c_1 = specific heat of metal = ?

c_2 = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

4.82\times c_1\times (34.5-110)=-[35\times 4.186\times (34.5-28.7)]

c_1=2.34J/g^oC

Hence, the specific heat of metal is 2.34 J/g°C

4 0
1 year ago
jin has four colorful glass bottles on his windowsill. one is red, one is violet, one is green, and one is yellow. the light tha
Over [174]
The red bottle would have the lowest frequency because red light has the longest wavelengths. The light passing through the violet would have the highest frequency because its wavelengths are the shortest.
4 0
2 years ago
Read 2 more answers
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