Answer:
(a) A strong acid has a greater tendency to lose its protons.
(b) A strong acid has a higher Ka than a weak acid.
(c) A strong acid has a lower pKa than a weak acid.
Explanation:
A strong acid has the ability to completely transfer their protons to the water, making a complete dissociation. Instead, a weak acid only dissociates partially, how much it dissociates depends on the acid dissociation constant (Ka).
The weak acids always are in equilibrium, and the equilibrium depends on the acid dissociation constant.
⇄ 
Thus, a stronger acid with a bigger Ka produces more dissociation and a higher concentration of protons.
The equation that defines pKa is:
Therefore, a higher pKa means a lower Ka and also a weaker acid.
Answer is: Kb for methylamine is 4.37·10⁻⁴.<span>
Chemical reaction: CH</span>₃NH₂ + H₂O → CH₃NH₃⁺ + OH⁻.
c(CH₃NH₂) = 0.253 M.
α = 4.07% ÷ 100% = 0.0407.
[CH₃NH₃⁺] = [OH⁻] = c(CH₃NH₂) · α.
[CH₃NH₃⁺] = [OH⁻] = 0.253 M · 0.0407.
[CH₃NH₃⁺] = [OH⁻] = 0.0103 M.
[CH₃NH₂] = 0.253 M - 0.0103 M.
[CH₃NH₂] = 0.2427 M.
Kb = [CH₃NH₃⁺] · [OH⁻] / [CH₃NH₂].
Kb = (0.0103 M)² / 0.2427 M.
Kb = 4.37·10⁻⁴.
6.28 mol O2 × 2 mol h2 / 1 mol 02 = 12.56 moles h2
Answer:
The equation for the reaction of one sodium bicarbonate ( NaHCO3 ) molecule with one citric acid (C6H8O7) molecule is the following:
Sodium Bicarbonate + Citric Acid ⇒ Water + Carbon Dioxide + Sodium Citrate
NaHCO3 + C6H8O7 ⇒ 3 CO2 + 3 H2O + Na3C6H5O7
Explanation:
The reaction is in balance, that is, the whole H2CO3 is not finished, but a little bit of this acid is left in the solution. Therefore, when sodium bicarbonate is added to the solution with citric acid, sodium citrate salt (C6H5O7Na3) and carbonic acid (H2CO3) are formed, which is rapidly broken down into water (H2O) and carbonic oxide (CO2).
C6H8O7 + NaHCO3 ⇒ C6H5O7Na3 + 3 H2CO3
C6H5O7Na3 + 3 H2CO3 ⇔ C6H5O7Na3 + 3 H2O + 3 CO2
Answer:
A. The moles of H(aq) equal the moles of OH
Explanation:
Thats what my chemistry teacher said Just trying to help out since theres no other answers.
