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qwelly [4]
2 years ago
6

Drag the terms to the appropriate blanks to complete the following sentences summarizing the redox reactions of photosynthesis.

Terms may be used once, more than once, or not at all. View Available Hint(s) ResetHelp NADP+ NADPH ATP ADP H2O CO2 O2 G3P 1. In the light reactions, light energy is used to oxidize NADP+ to NADPH. 2. The electrons derived from this oxidation reaction in the light reactions are used to reduce to . 3. The Calvin cycle oxidizes the light-reactions product to . 4. The electrons derived from this oxidation reaction in the Calvin cycle are used to reduce to .
Chemistry
1 answer:
quester [9]2 years ago
5 0
<h3><u>Answer;</u></h3>

1. In the light reactions, light energy is used to oxidize H2O to O2.

2. The electrons derived from this oxidation reaction in the light reactions are used to reduce NADP+ to NADPH.

3. The Calvin cycle oxidizes the light-reactions product NADPH to NADP+.

4. The electrons derived from this oxidation reaction in the Calvin cycle are used to reduce CO2 to G3P.

<h3><u>Explanation;</u></h3>
  • <em><u>In the light reactions, light energy is used to remove electrons from (oxidize) water, producing O2 gas. These electrons are ultimately used to reduce NADP+ to NADPH. </u></em>
  • In the Calvin cycle, NADPH is oxidized back to NADP+ (which returns to the light reactions). The electrons released by the oxidation of NADPH are used to reduce three molecules of CO2 to sugar (G3P), which then exits the Calvin cycle.
  • As ATP and NADPH are used in the Clavin cycle, they produce ADP and NADP+, respectively, which are returned to the light reactions so that more ATP and NADPH can be formed.
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The reaction SO2(g)+2H2S(g)←→3S(s)+2H2O(g) is the basis of a suggested method for removal of SO2 from power-plant stack gases. T
kifflom [539]

Answer : The equilibrium SO_2 pressure is, 3.93\times 10^{-5}torr

Explanation :

The given balanced chemical reaction is,

SO_2(g)+2H_2S(g)\rightleftharpoons 3S(s)+2H_2O(g)

First we have to calculate the standard free energy of reaction (\Delta G^o).

\Delta G^o=G_f_{product}-G_f_{reactant}

\Delta G^o=[n_{S(s)}\times \Delta G_f^0_{(S(s))}+n_{H_2O(g)}\times \Delta G_f^0_{(H_2O(g))}]-[n_{SO_2(g)}\times \Delta G_f^0_{(SO_2(g))}+n_{H_2S(g)}\times \Delta G_f^0_{(H_2S(g))}]

where,

\Delta G^o = standard free energy of reaction = ?

n = number of moles

Now put all the given values in this expression, we get:

\Delta G^o=[3mole\times (0kJ/mol)+2mole\times (-228.57kJ/mol)]-[1mole\times (-300.4kJ/mol)+2mole\times (-33.01kJ/mol)]

\Delta G^o=-90.72kJ/mol

Now we have to calculate the value of K_p

\Delta G^o=-RT\ln K_p

where,

\Delta G_^o =  standard Gibbs free energy  = -90.72 kJ/mol

R = gas constant = 8.314 J/mole.K

T = temperature = 298 K

K_p = equilibrium constant  = ?

Now put all the given values in this expression, we get:

-90.72kJ/mol=-(8.314J/mol.K)\times (298K) \ln K_p

K_p=7.98\times 10^{15}

Now we have to calculate the value of K_p.

The given balanced chemical reaction is,

SO_2(g)+2H_2S(g)\rightleftharpoons 3S(s)+2H_2O(g)

The expression for equilibrium constant will be :

K_p=\frac{(p_{H_2O})^2}{(p_{H_2S})^2\times (p_{SO_2})}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Let the equilibrium SO_2 pressure be, x

Pressure of SO_2 = Pressure of H_2S = x

Now put all the given values in this expression, we get

7.98\times 10^{15}=\frac{(22)^2}{(x)^2\times (x)}

x=3.93\times 10^{-5}torr

Thus, the equilibrium SO_2 pressure is, 3.93\times 10^{-5}torr

4 0
2 years ago
A graduated cylinder initially has 32.5 mL of water in it. After a 75.0 g piece of lead (Pb) is added to the graduated cylinder,
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Answer:

39.1-32.5 and you will find your answer it always like that, you subtract your starting point from your ending point

Explanation:

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2 years ago
Enter the net ionic equation representing solid chromium (iii) hydroxide reacting with nitrous acid. express your answer as a ba
Colt1911 [192]

The net ionic equation of chromium (iii) hydroxide reacting with nitrous acid:

Cr(OH)₃ (s) + 3H⁺ (aq) ⇒ Cr³⁺ (aq) + 3H₂O (l)

<h3>Further explanation</h3>

The electrolyte in the solution produces ions.

The equation of a chemical reaction can be expressed in the equation of the ions

For strong electrolytes (the ionization rate = 1) is written in the form of separate ions, while the weak electrolyte (degree of ionization <1) is still written as an un-ionized molecule

In the ion equation, there is a spectator ion that is the ion which does not change (does not react) because it is present before and after the reaction

When these ions are removed, the ionic equation is called the net ionic equation

For gases and solids including water (H₂O) can be written as an ionized molecule

So only the dissolved compound is ionized ((expressed in symbol aq)

From the problem, it is stated that chromium (iii) hydroxide reacting with nitrous acid.

Reactions that occur:

Cr(OH)₃ (s) + 3HNO₂ (aq) ⇒ Cr(NO₂)₃ (aq) + 3H₂O (l)

Cr (OH)₃ solid form that does not decompose in the form of ions, as well as water (H₂O)

So the ionic equation becomes:

Cr(OH)₃ (s) + 3H⁺ (aq) + 3NO₂⁻ (aq) ⇒ Cr³⁺ (aq) + 3NO₂⁻ (aq) + 3H₂O (l)

There is an ion spectator that is 3NO₂⁻, so that if it is removed a net ionic equation will be formed:

Cr(OH)₃ (s) + 3H⁺ (aq) ⇒ Cr³⁺ (aq) + 3H₂O (l)

<h3>Learn more</h3>

the net ionic equation

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Keywords: the net ionic equation, an ion spectator

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2 years ago
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What is the volume (in ml) of a 12.9 g piece of metal with a density of 7.25 g/cm3?
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Hey there:

1 cm³ = 1 mL

D = m  / V

7.25 = 12.9 / V

V = 12.9 / 7.25

V = 1.779 cm³
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It is important to know the difference between atoms, ions, and isotopes. Choose all of the correct answers. An atom of oxygen a
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The following are true:-

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