Question

Benzene, C6H6, reacts with oxygen, O2, to form CO2 and H2O. How much O2 is required for the complete combustion of 1.0 mol C6H6?

Answer 1

C6H6 + 02 forms CO2 + H20
Complete with factors to stabilize
C6H6 + 15/2 O2 forms 6 CO2 + 3 H2O
You take away only the info you need
C6H6 15/2 O2
1 mol 15/2 or 7,5 mol

15/2 or 7,5 mol of O2 are required.

;)

Answer 2

Answer:

7.5 mol of oxygen are required

Explanation:

Hi, as it says, this is a combustion reaction of benzene:

$C_6H_6(l) + O_2(g) \longrightarrow CO_2 (g) + H_2O (g)$

The first step is to balance the equation:

1 mol of $CO_2$ for each C in the benzene

1 mol of $H_2O$ for each two H in the benzene

1 mol of $O_2$ for each $CO_2$ and 0.5 mol for each $H_2O$

Balanced:

$C_6H_6(l) + 15/2 O_2(g) \longrightarrow 6 CO_2 (g) + 3 H_2O (g)$

Now, following the reaction:

For 1 mol of benzene, 15/2 (7.5) mol of oxygen are required.