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Otrada [13]
2 years ago
10

A sample of helium has a temperature of 450 K. The gas is cooled to 248.9 K at which time the gas occupies 103.4 L? Assume press

ure is constant at 3 atm. What was the original volume of the gas
Chemistry
2 answers:
Umnica [9.8K]2 years ago
5 0

Answer:

\boxed{\text{163.3 L}}

Explanation:

The pressure is constant, so, to calculate the volume, we can use Charles' Law:

\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}

Data:

V₁ = ?;            T₁ =    450 K

V₂ = 103.4 L; T₂ = 284.9 K

Calculation:

\dfrac{ V_{1}}{450} = \dfrac{ 103.4}{284.9}\\\\{ V_{1}} = 450 \times \dfrac{103.4}{284.9}\\\\ = \textbf{163.3 L}\\\text{The original volume of the helium was $\boxed{\textbf{163.3 L}}$}

IRINA_888 [86]2 years ago
5 0

The original volume of the gas is 186.94 Liters

Further Explanation;

<h3>Charles' Law </h3>
  • Charles's law states that the volume of a fixed mass of a gas is directly proportional to absolute temperature at constant pressure.

That is;V\alpha T

P=kT,  where k is a constant

At different temperatures and pressure then;

\frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }

In the Question;

We are given

V_{1} = ?\\T_{1} = 450\\V_{2} = 103.4 l\\T_{2} =248.9K

Therefore;

V_{1} =\frac{V_{2} T_{1} }{T_{2} }

V_{1} =\frac{(103.4 L)(450 K)}{(248.9K)}

V_{1} = 186.94Liters

<h3>Other Gas laws </h3><h3>Boyle's law </h3>
  • Boyle's law states that the volume of a fixed mass of a gas is inversely proportional to its pressure at a constant temperature.

That is;

P\alpha \frac{1}{V}

P\alpha \frac{k}{V}, where k is a constant

<h3>Combined gas law</h3>
  • Combined gas law combines both Boyle's law and Charles's law.
  • It states that the volume of a fixed mass of a gas is directly proportional to absolute temperature and inversely proportional to pressure.
  • That is;

\frac{P_{1}V_{1} }{T_{1} } = \frac{P_{2}V_{2} }{T_{2} }

<h3>Pressure Law</h3>
  • Pressure Law states that the pressure occupied by a gas is directly proportional to absolute temperature.

Keywords: Combined gas laws, Boyle's law and Charles's law

<h3>Learn more about:</h3>
  • Boyles’s law: brainly.com/question/1158880
  • Gay-Lussac’s law: brainly.com/question/2438000
  • Charles’s law:brainly.com/question/2438000
  • Combined gas law: brainly.com/question/2441061

Level: High school

Subject: Chemistry

Topic: Gas laws

Sub-topic: Charles's law

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Answer:

Explanation:

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The second resonance structure diagram for the ion given in the question can be found in the attached diagram below.

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Answer:

a) The reaction is first order, that is, order 1. Option C is correct.

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Explanation:

First of, we try to obtain the order of the reaction from the data provided.

t (minutes) [N2O5] (mol/L)

0 1.24x10-2

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Using a trial and error mode, we try to obtain the order of the reaction. But let's define some terms.

C₀ = Initial concentration of the reactant

C = concentration of the reactant at any time.

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For a zero order reaction, the general equation is

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It's evident the value of k isn't the same for the first 3 trials, hence, the reaction isn't a zero order reaction.

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