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lesya692 [45]
2 years ago
13

In terms of atomic structure, explain why the atomic radius of K is larger than that of Na

Chemistry
1 answer:
oee [108]2 years ago
7 0

Answer:

Explanation:

Sodium and potassium are present in group 1A. Both are alkali metals.

The atomic number of sodium is 11 and potassium is 19. Sodium is present in period 3rd while potassium is present in period 4th.

Electronic configuration of sodium:

Na₁₁ = 1s² 2s² 2p⁶ 3s¹

K₁₉ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹

It can be seen in electronic configuration that in case of sodium the valance electron is present in third energy level while in case of K outer most  electron is present in 4th energy level. So atomic structure of sodium has three energy level and K has four energy  level that's why radius of potassium is greater than sodium because its the distance from center to outer most electronic shell.

Moreover as we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

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A student sets up the following equation to convert a measurement. (The stands for a number the student is going to calculate.)
Aliun [14]

The question is incomplete, here is the complete question:

A student sets up the following equation to convert a measurement. (The stands for a number the student is going to calculate.) Fill in the missing part of this equation.

23.Pa.cm^3=?kPa.m^3

<u>Answer:</u> The measurement after converting is 23\times 10^{-9}kPa.m^3

<u>Explanation:</u>

We are given:

A quantity having value 23.Pa.cm^3

To convert this into kPa.m^3, we need to use the conversion factors:

1 kPa = 1000 Pa

1m^3=10^6cm^3

Converting the quantity into kPa.m^3, we get:

\Rightarrow 23.Pa.cm^3\times (\frac{1kPa}{1000Pa})\times (\frac{1m^3}{10^6cm^3})\\\\\Rightarrow 23\times 10^{-9}kPa.m^3

Hence, the measurement after converting is 23\times 10^{-9}kPa.m^3

6 0
2 years ago
Which procedure cannot be performed on a hot plate, requiring a Bunsen burner instead
ankoles [38]

Answer: Heating a crucible to remove water from a hydrate.

Explanation:

The options are:

a. Heating a solvent to help a solute dissolve.

b. Heating an isolated solid to dry it.

c. Heating water to boiling for a water bath.

d. Heating a crucible to remove water from a hydrate.

The procedure that can be performed on a hot plate are:

a. Heating a solvent to help a solute dissolve.

b. Heating an isolated solid to dry it.

c. Heating water to boiling for a water bath.

It should be noted that the hot plate cannot be used for heating of crucible in order to remove water from a hydrate. It is not advisable for someone to heat any silica or ceramic objects on a hot plate.

Therefore, heating a crucible to remove water from a hydrate is the correct option.

4 0
2 years ago
A deck of cards has dimensions 8.9cm x 5.72cm x 1.82 cm. What is the volume of the deck in cubic centimeters?
arsen [322]

Answer:

92.65256 cm^3

Explanation:

To find this, we can simply multiply all three dimensions to get the answer in cubic centimeters, and we get the answer above. If you want to be more specific, we can go by the sigfig rule and the answer would be rounded to 93 cm^3.

5 0
2 years ago
_________is a process in which o2 is released as a by-product of oxidation-reduction reactions
Kisachek [45]

Answer : The combustion is a process in which oxygen is released as a by-product of oxidation-reduction reactions.

Explanation :

Combustion reaction : It is defined as the reactions in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide and water.

The chemical equation of combustion reaction is:

CH_4+2O_2\rightarrow CO_2+2H_2O

The combustion reaction is also a redox reaction.

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

The combustion reaction is also a redox reaction in which the carbon shows oxidation by the addition of oxygen or removal of hydrogen and oxygen shows reduction by the addition of hydrogen or removal of oxygen.

Hence, the combustion is a process in which oxygen is released as a by-product of oxidation-reduction reactions.

6 0
2 years ago
At 10°c one volume of water dissolves 3.10 volumes of chlorine gas at 1.00 atm pressure. what is the henry's law constant of cl2
s344n2d4d5 [400]
Answer is:  0,133 mol/ l· atm.
T(chlorine) = 10°C = 283K.
p(chlorine) = 1 atm.
V(chlorine) = 3,10 l.
R - gas constant, R = 0.0821 atm·l/mol·K. 
Ideal gas law: p·V = n·R·T
n(chlorine) = p·V ÷ R·T.
n(chlorine) = 1atm · 3,10l ÷ 0,0821 atm·l/mol·K · 283K = 0,133mol.
Henry's law: c = p·k.
k - <span>Henry's law constant.
</span>c - solubility of a gas at a fixed temperature in a particular solvent.
c = 0,133 mol/l.
k = 0,133 mol/l ÷ 1 atm = 0,133 mol/ l· atm.

4 0
2 years ago
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