Which step should be next in this procedure? List the materials that are needed. Write a conclusion for the experiment. Write a
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<em>The mass of a gold bar = 1.424 x 10⁴ gram</em>
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<h3><em>Further Explanation</em></h3>Density is a quantity derived from the mass and volume
density is the ratio of mass per unit volume
With the same mass, the volume of objects that have a high density will be smaller than type
The unit of density can be expressed in g / cm3 or kg / m3
Density formula:
ρ = density
m = mass
v = volume
A common example is the water density of 1 gr / cm3
The mass itself is often equated with weight, even though it is different. Mass is the amount of matter in the matter while weight is related to the gravitational force
<em>Known variable</em>
volume gold bar 7.379 × 10⁻⁴ m³
a density of 19.3 g/cm³
<em>Asked</em>
the mass of a gold bar
<em>Answer</em>
volume is known to be 7.379 × 10⁻⁴ m³, then we change it first to units of cm³ adjusting to units of density
7.379 × 10⁻⁴ m³ = 7.379 × 10² cm³
then:
mass = volume x density
mass = 7.379 × 10² cm³ x 19.3 g/cm³
mass = 1.424 x 10⁴ gram
<h3><em>Learn more </em></h3>density acetone
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Keywords: density, mass, volume, a gold bar
The Lewis structure for H₂CO is shown in the attached picture. The central atom is the carbon. However, I'm not sure which bond you're referring to. There can be two answers. The two C-H bonds are sp³ hybridized because it is a single bond. The C=O bond is sp² hybridized because it is a double bond.
