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anzhelika [568]

1 year ago

8

Which step should be next in this procedure? List the materials that are needed. Write a conclusion for the experiment. Write a

hypothesis for the results. Draw a table for the observations.

1 answer:

vladimir1956 [14]1 year ago

5 0

Where is the question?

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25.0 ml of a 6.0 m hno3 stock solution is diluted using water to 100 ml. How many moles of hno3 are present in the dilute soluti

lana66690 [7]

Answer:

The answer to your question is: 6 moles of HNO₃

Explanation:

Data

Volume = 25 ml

Concentration = 6 M HNO₃

Diluted 100 ml

Formula

Molarity = # moles / volume

# of moles = Volume x Molarity

Process

# of moles = 0.10 x 6

= 6 moles

6 0

2 years ago

Read 2 more answers

Match each situation below to a letter on the illustration.

Mnenie [13.5K]

Answer:a

Explanation:

4 0

1 year ago

A 0.580 g sample of a compound containing only carbon and hydrogen contains 0.480 g of carbon and 0.100 g of hydrogen. At STP, 3

Sati [7]

Answer:

Molecular formula for the gas is: C₄H₁₀

Explanation:

Let's propose the Ideal Gases Law to determine the moles of gas, that contains 0.087 g

At STP → 1 atm and 273.15K

1 atm . 0.0336 L = n . 0.082 . 273.15 K

n = (1 atm . 0.0336 L) / (0.082 . 273.15 K)

n = 1.500 × 10⁻³ moles

Molar mass of gas = 0.087 g / 1.500 × 10⁻³ moles = 58 g/m

Now we propose rules of three:

If 0.580 g of gas has ____ 0.480 g of C _____ 0.100 g of C

58 g of gas (1mol) would have:

(58 g . 0.480) / 0.580 = 48 g of C

(58 g . 0.100) / 0.580 = 10 g of H

48 g of C / 12 g/mol = 4 mol

10 g of H / 1g/mol = 10 moles

7 0

2 years ago

What is the product of one equivalent of phosphorus and three equivalents of hydrogen? Draw it's

yulyashka [42]

This name is phosphine flammable , toxic gas colourless
...it's formula is PH3

6 0

2 years ago

Water at 4.4°C is to flow through a horizontal, commercial steel pipe having a length of 305 m at the rate of 150 gal/min. If a

Pavel [41]

Answer:

d = 70.5 mm

Explanation:

given,

length of pipe = 305 m

discharge rate = 150 gal/min

pipe diameter = ?

1 gal/min = 6.30902 × 10⁻⁵ m³/s

150 gal/min = 150 × 6.30902 × 10⁻⁵ m³/s

= 9.46 × 10⁻³ m³/s

$h = \dfrac{flv^2}{2gd}$

$h = \dfrac{flv^2}{2gd}$

Q = A V

$h = \dfrac{fl(\dfrac{Q}{A})^2}{2gd}$

$h = \dfrac{fl(\dfrac{Q}{\dfrac{\pi}{4}d^2})^2}{2gd}$

$h= \dfrac{8flQ^2}{\pi^2gd^5}$

f = 0.048 from moody chart using P/D = 0.00015

$\dfrac{1}{d^5}= \dfrac{6.1\times \pi^2\times 9.8}{8\times 0.048\times 305\times 0.00946^2}$

d = 70.5 mm

Diameter of the pipe is equal to 70.5 mm

7 0

2 years ago