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1 year ago

In an electric field, which emanation is deflected toward the negative electrode

1 answer:

4 0

If a type of radiation is attracted to the negative electrode, then it must have a positive charge. Beta particles are electrons and are negative. X-rays and gamma rays are essentially the same thing and are electromagnetic energy. They have no charge. The difference between X-rays and gamma rays is how they are produced*. Your answer is alpha radiation. An alpha particle is the nucleus of a helium atom and carries a +2 charge.

* Gamma rays are a product of the random nuclear decay of unstable nuclei. X-rays are produced when high speed electrons are caused to stop or slow down. The kinetic energy of the electron is converted to electromagnetic energy. X-rays and gamma rays are not particles and do not carry a charge, and cannot be attracted or deflected from charged electrodes.

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Use enthalpies of formation given in appendix c to calculate δh for the reaction br2(g)→2br(g), and use this value to estimate t

Contact [7]

Given reaction represents dissociation of bromine gas to form bromine atoms

Br2(g) ↔ 2Br(g)

The enthalpy of the above reaction is given as:

ΔH = ∑n(products)Δ $H^{0}f(products)$ - ∑n(reactants)Δ $H^{0}f(reactants)$

where n = number of moles

Δ $H^{0}f$ = enthalpy of formation

ΔH = [2*ΔH(Br(g)) - ΔH(Br2(g))] = 2*111.9 - 30.9 = 192.9 kJ/mol

Thus, enthalpy of dissociation is the bond energy of Br-Br = 192.9 kJ/mol

3 0

2 years ago

When 1.04g of cyclopropane was burnt in excess oxygen in a bomb calorimeter, the temperature rose by 3.69K. The total heat capac

STatiana [176]

Answer:

$\Delta _{comb}H=-2,093\frac{kJ}{mol}$

Explanation:

Hello!

In this case, since these calorimetry problems are characterized by the fact that the calorimeter absorbs the heat released by the combustion of the substance, we can write:

$Q_{rxn}+Q_{cal}=0$

Thus, given the temperature change and the total heat capacity, we obtain the following total heat of reaction:

$Q_{rxn}=-14.01kJ/K*3.69K\\\\Q_{rxn}=-51.70kJ$

Now, by dividing by the moles in 1.04 g of cyclopropane (42.09 g/mol) we obtain the enthalpy of combustion of this fuel:

$n=\frac{1.04g}{42.09g/mol}=0.0247mol\\\\\Delta _{comb}H=\frac{Q_{rxn}}{n}\\\\ \Delta _{comb}H=-2,093\frac{kJ}{mol}$

Best regards!

4 0

1 year ago

An ice cube is dropped into a glass of milk at 20°C. Which statement explains the transfer of kinetic energy (KE)?

hoa [83]

Answer:

Because milk has higher KE than ice, KE is transferred from the milk to the molecules of ice.

Explanation:

The best statement that expresses the transfer of kinetic energy(K.E) is that kinetic energy is transferred from the milk to the ice.

Kinetic energy is form of energy due to motion of the particles of a medium. In this regard, we are dealing with heat energy.

Heat energy is dissipated from a body at higher temperature to one at a lower temperature.
Ice is at a lower temperature which is 0°C
Heat will be transferred in form of thermal energy from the body at higher temperature to one with a lower temperature.
This is from the milk to the molecules of ice.

3 0

1 year ago

A 100 mL reaction vessel initially contains 2.60×10^-2 moles of NO and 1.30×10^-2 moles of H2. At equilibrium the concentration

Sliva [168]

Answer:

<h2>The equilibrium constant Kc for this reaction is 19.4760</h2>

Explanation:

The volume of vessel used= $100$ ml