Lets take 100 g of this compound,
so it is going to be 2.00 g H, 32.7 g S and 65.3 g O.
2.00 g H *1 mol H/1.01 g H ≈ 1.98 mol H
32.7 g S *1 mol S/ 32.1 g S ≈ 1.02 mol S
65.3 g O * 1 mol O/16.0 g O ≈ 4.08 mol O
1.98 mol H : 1.02 mol S : 4.08 mol O = 2 mol H : 1 mol S : 4 mol O
Empirical formula
H2SO4
<span>The extracellular fluid is high in NaCl so the cell would be dehydrated further and the two solutions would equilibrate. Ultimately water would leave the cell and passes to </span>extracellular fluid and equilibrium is reached.
A) 5.2 x 10^2
B) 86.
C) 6.4 x 10^3
D) 5.0
E) 22.
F) 0.89
<span>The mass (in grams) of 8.45 x 10^23 molecules of dextrose is 252.798g
Working:
Mw. dextrose is 180.16 g/mol
therefore 180.16 grams dextrose = 1 mole
therefore 180.16 grams dextrose= 6.022x10^23 molecules (Avogadro's number)
We have 8.45 x 10^23 molecules of dextrose.
Therefore, (180.16 divided by 6.022x10^23) times 8.45x10^23
gives the mass (in grams) of 8.45 x 10^23 molecules of dextrose;
252.798.</span>
Answer:
Heat transferred, Q = 1542.42 J
Explanation:
Given that,
Mass of water, m = 30 grams
Initial temperature, 
Final temperature, 
We need to find the energy transferred. The energy transferred is given by :
c is specific heat of water, c = 4.18 J/g °C
So,
So, 1542.42 J of energy is transferred.
