The heat of combustion for methanol is 727 kj/mol
<em><u>calculation</u></em>
calculate the moles of methanol (CH3OH)
moles = mass/molar mass
molar mass of methanol = 12 +( 1 x3) +16 + 1= 32 g /mol
moles is therefore= 64.0 g / 32 g/mol = 2 moles
Heat of combustion is therefore = 1454 Kj / 2 moles = 727 Kj/mol
The oil slick thick = 1.256 x 10⁻⁴ cm
<h3>Further explanation</h3>
Volume is a derivative quantity derived from the length of the principal
The unit of volume can be expressed in liters or milliliters or cubic meters
The conversion is
1 cc = 1 cm3
1 dm = 1 Liter
1 L = 1.06 quart
<em>so for 1 quart = 0.943 L</em>
Volume of oil dumped = volume of swimming pool
D has a total of four significant figures.
Molybdenum Arsenide
I think that’s right but not %100 sure
The temperature reached after four hours of cooling is 140 F (or) 42 C.
Explanation:
A food worker cooled a cup of soup for two hours,
step 1: The temperature reached in <u>two hours</u>= 70 F (or) 21 C
step 2: Then for <u>four hours</u>, <u>it is twice the value</u>
∴ The temperature reached in four hours= 2(70)= 140 F (or) 2(21)= 42 C
