What is the number of moles in 15.0 g AsH3?
1 answer:
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Here, the three different notation of the p-orbital in different sub-level have to generate
The value of azimuthal quantum number (l) for -p orbital is 1. We know that the magnetic quantum number depends upon the value of l, which are -l to +l.
Thus for p-orbital the possible magnetic quantum numbers are- -1, 0, +1. So there will be three orbitals for p orbitals, which are designated as ,
and
in space.
The three p-orbital can be distinguish by the quantum numbers as-
For 2p orbitals (principal quantum number is 2)
1) n = 2, l = 1, m = -1
2) n = 2, l = 1, m = 0
3) n = 2, l = 1, m = +1
Thus the notation of different p-orbitals in the sub level are determined.
Answer: The concentration of excess in solution is 0.017 M.
Explanation:
1.
moles of
1 mole of give = 1 mole of
Thus 0.019 moles of give = 0.019 mole of
2. moles of
According to stoichiometry:
1 mole of gives = 2 moles of
Thus 0.012 moles of give =
moles of
As 1 mole of neutralize 1 mole of
0.019 mole of will neutralize 0.019 mole of
Thus (0.024-0.019)= 0.005 moles of will be left.
Thus molarity of in solution is 0.017 M.
Answer : The number of moles of oxygen present in a sample are 11.3 moles.
Explanation :
The given compound is,
By the stoichiometry we can say that, 1 mole of of has 4 moles of CO.
Or we can say that, 1 mole of of has 1 mole of nickel (Ni), 4 moles of carbon (C) and 4 moles of oxygen.
That means,
Number of moles of carbon = Number of moles of oxygen
As we are given that:
Number of moles of carbon = 11.3 moles
So, number of moles of oxygen = number of moles of carbon = 11.3 moles
Therefore, the number of moles of oxygen present in a sample are 11.3 moles.