Answer:
Explanation:
At the cathode
In case of molten AgI
Silver will be collected
In case of molten LiI
lithium will be collected
in case of aqueous LiI,
hydrogen gas will be collected as reduction potential of H⁺ is more than Li⁺
in case of aqueous AgI,
Silver will be obtained at cathode because reduction potential of silver is more than H⁺
At the Anode
In case of molten NaBr
Bromine will be collected
In case of molten NaF
Fluorine will be collected
in case of aqueous NaBr ,
Bromine will be collected as reduction potential of Br⁻ is less than O⁻²
in case of aqueous NaF ,
oxygen will be obtained because reduction potential of F⁻ is more than O⁻² .
Answer:
Concentration, because the amounts of reactants and products remain constant after equilibrium is reached.
Explanation:
The rate of reaction refers to the amount of reactants converted or products formed per unit time.
As the reaction progresses, reactions are converted into products. This continues until equilibrium is attained in a closed system.
When equilibrium is attained, the rate of forward reaction is equal to the rate of reverse reaction, hence the concentration of reactants and products in the system remain fairly constant over time.
When deducing the rate of reaction, concentration of the specie of interest is plotted on the y-axis against time on the x-axis.
The answer to this question would be: <span>thermal metamorphism
</span>
Metamorphism is a change in the mineral texture without causing the rock to become liquid/magma. In this case, the metamorphic change to the rock is caused by the heat energy or thermal energy of the magma. This kind of mechanism is also called contact mechanism as the thermal energy is transferred by contact so this question option is a bit ambiguous.
<span>At standard temperature and pressure 22.4 l of an ideal gas would contain 1 mole. in order to find the change in moles we must look at the ideal gas law PV=nRT where P=Pressure V=volume n=Moles R= Gas constant T= Temperature. To simplify this equation we will be using the gas constant at .08206 L-atm/mol-K. We must first convert 100c to k which is 373.15. Then we can plug the values into our equation which gives us (2atm)(14.5 l)=(n)(.08206 L-atm/mol-K)(373.15). After some basic algebra we get the moles to equal roughly .95 which is .05 moles less than our original system.</span>
