Start with the ingestion of food on the left. Eating food provides fuel & building blocks for your body, after food is broke down in the digestive system, it is transported to cells via the circulatory system, fuel molecules are broken down further in glycolysis& the citric acid cycle, ATP is produced with <span>the help of the electron transport chain.</span>
Molar mass O₂ = 32.0 g/mol and N₂ = 28.0 g/mol
N₂ +2 O₂ → 2 NO₂
28.0 g -------> 32.0 * 2
7 g ----------> ?
Mass of O₂ = 7 * 32.0 * 2 / 28.0
Mass of O₂ = 448 / 28.0
= 16 g of O₂
Answer B
hope this helps!
Answer:
0.74 grams of methane
Explanation:
The balanced equation of the combustion reaction of methane with oxygen is:
it is clear that 1 mol of CH₄ reacts with 2 mol of O₂.
firstly, we need to calculate the number of moles of both
for CH₄:
number of moles = mass / molar mass = (3.00 g) / (16.00 g/mol) = 0.1875 mol.
for O₂:
number of moles = mass / molar mass = (9.00 g) / (32.00 g/mol) = 0.2812 mol.
- it is clear that O₂ is the limiting reactant and methane will leftover.
using cross multiplication
1 mol of CH₄ needs → 2 mol of O₂
??? mol of CH₄ needs → 0.2812 mol of O₂
∴ the number of mol of CH₄ needed = (0.2812 * 1) / 2 = 0.1406 mol
so 0.14 mol will react and the remaining CH₄
mol of CH₄ left over = 0.1875 -0.1406 = 0.0469 mol
now we convert moles into grams
mass of CH₄ left over = no. of mol of CH₄ left over * molar mass
= 0.0469 mol * 16 g/mol = 0.7504 g
So, the right choice is 0.74 grams of methane
The reaction of NaOH and HCl is as follows: NaOH+HCl⇒NaCl+H2O. So the ratio between the two reactants is NaOH:HCl=1:1. According to the question, the moles of NaOH needed to neutralize the acid is 0.243M*0.04633L=0.01126mole. Because is the above ratio (1:1), the moles of acid that are being neutralized is also 0.01126mole. So the concentration of the acid is 0.01126mole/0.010L = 1.126 M.
