All categories

2 years ago

A lead cylinder has a mass of 540 grams and a density of 2.70 g/ml. What is its volume

Chemistry

2 answers:

ch4aika [34]2 years ago

3 0

Volume = Mass / Density

Volume = 540g / 2.70 g/ml

Volume = 200 ml

Solnce55 [7]2 years ago

3 0

Answer:

Volume of the cylinder is, $V=200\ ml$

Explanation:

It is given that,

Mass of the cylinder, m = 540 grams

Density of the cylinder, $d=2.7\ g/ml$

Let V is the volume of the material. We know that the mass per unit volume of any material is called its density. The mathematical relation is given by :

$d=\dfrac{m}{V}$

$V=\dfrac{m}{d}$

$V=\dfrac{540\ g}{2.7\ g/ml}$

$V=200\ ml$

So, the volume of the cylinder is $200\ ml$ . Hence, this is the required solution.

You might be interested in

B5H9(l) is a colorless liquid that will explode when exposed to oxygen. How much heat is released when 0.211 mol of B5H9 reacts

n200080 [17]

Answer:

Heat realesed is - 2192.7 kJ

Explanation:

First lets have the chemical equation balanced, and then solve the question based on the fact that the enthalpy change for a reaction is the sum of the enthalpies of formation of products minus reactants.

B₅H₉ (l) + O₂ (g) ⇒ B₂O₃ (s) + H₂O(l)

B atoms we have 5 reactants and 2 products, so the common mltiple is 10 and we have

2 B₅H₉ (l) + O₂ (g) ⇒ 5 B₂O₃ (s) + H₂O(l)

Now balance H by multiplying by 9 the H₂O

2 B₅H₉ (l) + O₂ (g) ⇒ 5 B₂O₃ (s) + 9 H₂O(l)

Finally, balance the O since we have 24 in products by multiplying by 12 the

O₂ ,

2 B₅H₉ (l) + 12 O₂ (g) ⇒ 5 B₂O₃ (s) + 9 H₂O

ΔHrxn = 5 x ΔHºf B₂O₃ + 9 x ΔHºf H₂O - ( 2 x ΔHºf B₅H₉ + 12 x ΔHºf O₂ )

We have all the ΔHºf s except oxygen but remember the enthalpy of formation of a pure element in its standard estate is cero.

ΔHrxn = 5 mol x ( -1272 kJ/mol )+ 9 mol x ( -285.4 kJ/mol ) - ( 2mol x 732 kJ/mol )

= -8928.6 kJ - 1464 kJ = -10,392 kJ

Now this enthalpy change was based in 2 mol reacted according to the balanced equation, so for 0.211 mol of B₅H₉ we will have:

-10,392 kJ/ 2 mol B₅H₉ x 0.211 mol B₅H₉ = - 2192.7 kJ

8 0

2 years ago

Read 2 more answers

Substitution of an amino group on the para position of acetophenone shifts the cjo frequency from about 1685 to 1652 cm−1 , wher

cluponka [151]

Answer:

Here's what I get.

Explanation:

The frequency of a vibration depends on the strength of the bond (the force constant).

The stronger the bond, the more energy is needed for the vibration, so the frequency (f) and the wavenumber increase.

Acetophenone

Resonance interactions with the aromatic ring give the C=O bond in acetophenone a mix of single- and double-bond character, and the bond frequency = 1685 cm⁻¹.

p-Aminoacetophenone

The +R effect of the amino group increases the single-bond character of the C=O bond. The bond lengthens, so it becomes weaker.

The vibrational energy decreases, so wavenumber decreases to 1652 cm⁻¹.

p-Nitroacetophenone

The nitro group puts a partial positive charge on C-1. The -I effect withdraws electrons from the acetyl group.

As electron density moves toward C-1, the double bond character of the C=O group increases.

The bond length decreases, so the bond becomes stronger, and wavenumber increases to 1693 cm¹.

6 0

2 years ago

George is writing a newspaper article about the fire at the local library. His introductory paragraph has an example of conserva

Lina20 [59]

Answer:

Explanation:

7 0

2 years ago

Read 2 more answers

Please Help Me!!

Cerrena [4.2K]

Answer:

1. Galvanic oxidation. Example is the corrosion of aluminium wires when in contact with copper wires under wet conditions.

2. Rainwater or Damp/moist air

3. Chromium-plated steel screws or stainless steel screws or galvanized steel screws

Explanation:

1. Galvanic oxidation or corrosion occurs when two different metals with different electrode potentials are brought into contact with each other by means of an electrolyte (usually a aqueous solution), such that a redox reaction occurs leading to one metal with the more negative electrode potential (the anode) becoming oxidized, while the other less negative potential (the cathode) is reduced.

In order for galvanic corrosion to occur, three elements are required.

i. Two metals with different corrosion potentials (anode and cathode)

ii. Direct metal-to-metal electrical contact

iii. A conductive electrolyte solution (e.g. water) must connect the two metals on a regular basis.

For example oxidation (corrosion) of aluminium wires when in contact with copper wire under wet conditions.

2. The most likely electrolyte will be rainwater containing dissoved solutes (if the panel is in an exposed part of the house) or damp/moist air.

3. From the table, the most likely screw will be chromium-plated steel screws or stainless steel (made of iron and nickel) screws or galvanized steel (zinc-plated) screws.

All these possible screw components have a more negative electrode potential than copper. Thus they will serve as the anode in a galvanic oxidation with copper.

3 0

2 years ago

Identify the statements that correctly describe the saturation temperature of a solution. Select one or more:_________ a. Any te

Alexeev081 [22]

Answer:

The correct options are "b" and "c". A further explanation is given below.

Explanation:

Saturation temperature can be determined where this enough of some other solution that is incorporated like that can be absorbed by a solvent.
The formulation is saturated at this same stage, so Ksp could be computed. As well as the solid throughout solution should continue to appear upon freezing below a certain temperature.

The other options offered aren't relevant to the situation described. So the equivalents above are the right ones.

8 0

2 years ago