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2 years ago

A lead cylinder has a mass of 540 grams and a density of 2.70 g/ml. What is its volume

Chemistry

2 answers:

ch4aika [34]2 years ago

3 0

Volume = Mass / Density

Volume = 540g / 2.70 g/ml

Volume = 200 ml

Solnce55 [7]2 years ago

3 0

Answer:

Volume of the cylinder is, $V=200\ ml$

Explanation:

It is given that,

Mass of the cylinder, m = 540 grams

Density of the cylinder, $d=2.7\ g/ml$

Let V is the volume of the material. We know that the mass per unit volume of any material is called its density. The mathematical relation is given by :

$d=\dfrac{m}{V}$

$V=\dfrac{m}{d}$

$V=\dfrac{540\ g}{2.7\ g/ml}$

$V=200\ ml$

So, the volume of the cylinder is $200\ ml$ . Hence, this is the required solution.

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<em>Acetone (C₃H₆O) has a boiling point of 56.5 °C. How many grams of the acetone vapor would occupy the 250 mL Erlenmeyer flask at 57 °C and 730 mmHg?</em>

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Step 1: Given data

Temperature (T): 57°C

Pressure (P): 730 mmHg

Volume (V): 250 mL

Step 2: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15 = 57°C + 273.15 = 330 K

Step 3: Convert "P" to atm

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730 mmHg × (1 atm/760 mmHg) = 0.961 atm

Step 4: Convert "V" to L

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Step 5: Calculate the moles (n) of acetone

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 0.961 atm × 0.250 L/(0.0821 atm.L/mol.K) × 330 K

n = 8.87 × 10⁻³ mol

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The molar mass of acetone is 58.08 g/mol.

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