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Damm [24]
2 years ago
7

During an endothermic reaction, H for the reactants was −600 kJ/mol. Which of the following statements is correct about the H fo

r the products and the comparison of the energy in bonds?
A. It is less than −600 kJ/mol, and the amount of energy required to break bonds is greater than the amount of energy released in forming bonds.

B. It is less than −600 kJ/mol, and the amount of energy required to break bonds is less than the amount of energy released in forming bonds.

C. It is greater than −600 kJ/mol, and the amount of energy required to break bonds is greater than the amount of energy released in forming bonds.

D. It is greater than −600 kJ/mol, and the amount of energy required to break bonds is less than the amount of energy released in forming bonds.
Chemistry
2 answers:
o-na [289]2 years ago
7 0

Answer:

C. It is greater than -600 kJ/mol, and the amount required to break bonds is greater than the amount of energy released in forming bonds.  

Explanation:

As a reaction occurs, bonds of reactants are broken and new bonds are formed in products. During bond breaking energy is absorbed while during bond formation energy is released. If the energy released during bond formation is greater than the energy absorbed during bond breaking, then the reaction is exothermic. If the energy released during bond formation is less than energy absorbed during bond breaking, then the reaction is endothermic.

If reactants have less energy than products, it means more energy is absorbed than released thus it is an endothermic reaction.

If reactants have more energy than products, it means more energy is released than absorbed thus it is an exothermic reaction.

anastassius [24]2 years ago
7 0

Answer:

its c

Explanation:

i took the exam

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ddd [48]

Answer :

The enthalpy of reaction is, -187.6 kJ/mol

The total heat will be, -2251 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

(a) The formation of CH_4 will be,

2C(coal)+2H_2O(g)\rightarrow CH_4(g)+CO_2(g)    \Delta H_{rxn}=?

The intermediate balanced chemical reaction will be,

(1) C(coal)+H_2O(g)\rightarrow CO(g)+H_2(g)     \Delta H_1=29.7kJ

(2) CO(g)+H_2O(g)\rightarrow CO_2(g)+H_2(g)    \Delta H_2=-41kJ

(3) CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2O(g)    \Delta H_3=-206kJ

We are multiplying equation 1 by 2 and then adding all the equations, we get :

(b) The expression for enthalpy of reaction will be,

\Delta H_{rxn}=2\times \Delta H_1+\Delta H_2+\Delta H_3

\Delta H_{rxn}=(2\times 29.7)+(-41)+(-206)

\Delta H_{rxn}=-187.6kJ/mol

Therefore, the enthalpy of reaction is, -187.6 kJ/mol

(c) Now we have to calculate the total heat.

\Delta H=\frac{q}{n}

or,

q=\Delta H\times n

where,

\Delta H = enthalpy change = -187.6 kJ/mol

q = heat = ?

n = number of moles of coal = \frac{1.00\times 1000g}{12.00g/mol}=83.33mol

Now put all the given values in the above formula, we get:

q=(-187.6kJ/mol)\times (83.33mol)=-2.251kJ

Thus, the total heat will be, -2251 kJ

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2 years ago
If the concentration of a reactant is tripled (all other things remain constant), and the reaction rate increases nine times, wh
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2 years ago
acetaminophen is a stronger acid than methanol, and sodium methoxide is a stronger base than. write an acid base equilibrium rea
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Answer:

The equilibrium shifts to the right that is the forward reaction.

Explanation:

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The reaction between Acetaminophen and sodium methoxide gives methanol and acetaminophen sodium salt. Therefore, the acid base equilibrium reaction of these species is given as;

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8 0
2 years ago
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To find how many grams are in 4 moles, times 121.99 by 4
This gives you 487.96

But the questions asks for the answer to be in kilograms nor grams, to change into kilograms divide by 1000
This gets you the answer: 0.49 kg

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