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sattari [20]
1 year ago
11

Suppose you had used carbon tetrachloride, a liquid of density 2.20 g/mL, to determine the actual volume measured by your pipet.

What differences would there be in mass of the liquid measured and the actual volume of liquid measured for carbon tetrachloride compared to the same values for water?
Chemistry
1 answer:
VARVARA [1.3K]1 year ago
4 0

Answer:

Carbon tetrachloride would be 2.2 fold heavier than water

Explanation:

Carbon tetrachloride (2.20g/mL) is denser than water (1.00g/mL)

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The oxidation of methanol to formaldehyde can be accomplished by reaction with chromic acid: 6H+ + 3CH3OH + 2H2CrO4 → 3CH2O + 2C
babunello [35]

Lo que está marcado con rojo (el ejercicio)

7 0
1 year ago
If the concentration of a saturated solution at 0∘C is 12.5 gCuSO4/100 g soln, what mass of CuSO4⋅5H2O would be obtained? [Hint:
Andrew [12]

Answer:

Mass of CuSO4.H2O obtained: m_{total}=19.52 g

Explanation:

The molecular weight of the salt is: M=159.5 g/mol

<u>In the solution</u>: 12.5 g of CuSO4

In moles: n=\frac{12.5 g}{159.5 g/mol}=0.078 mol

<u>Mass of wate</u>r:

5 moles of water per mol of salt: m=\frac{5mol}{1mol}*0.078mol*\frac{18g}{mol}=7.02 g

Mass of CuSO4.H2O obtained: m_{total}=12.5 g + 7.02 g=19.52 g

7 0
2 years ago
What volume in milliliters of 6.0 M NaOH is needed to prepare 175mL of 0.20 M NaOH by dilution?
Ilya [14]

Answer:

V¹N²= V²N²

here V¹= ?

N¹= 6.00

V²= 175ml

M²= 0.2M

So V¹= (V²N²)/N² = (175 x 0.2)/6

V¹ = 5.83 ml

Explanation:

Therefore diluting 5.83 ml of 6.00M NaOH to 175 m l ,we get 0.2M Solution.

4 0
1 year ago
Question 2: Phase Changes (14 points) a. Rewrite each of the following equations for phase changes, to include the heat required
lilavasa [31]

Explanation:

(i)  The equilibrium reaction equation will be as follows.

              H_{2}O(l) \rightleftharpoons  H_{2}O(s)

A reaction in which there will be absorption of heat energy is known as endothermic reaction.

A reaction in which there will be release of heat energy is known as exothermic reaction.

As liquid state of water is changing into solid state. So, it means that molecules of water came close to each other. Hence, there will be release of heat this means that reaction is exothermic in nature.

Hence, phase change from liquid to solid will be exothermic in nature.

Latent heat of fusion is defined as the amount of energy necessary to convert 1 gram of a solid into liquid state at its melting point.

So, when solid state of water changes into liquid state then it means energy is absorbed by the molecules of ice due to which they have gained kinetic energy. Hence, they moved away from each other leading to formation of liquid state of water.

Latent heat of freezing of liquid water is 334 J/g.

Specific heat of liquid water is 4.186 J/g ^{o}C

Specific heat of steam is 1.996 kJ/kg/^{o}K

Specific heat of ice is 2.1 kJ/kg/^{o}K

(ii)  The equilibrium reaction equation will be as follows.

              H_{2}O(l) \rightleftharpoons H_{2}O(g)

As liquid state of water is changing into gaseous or vapor state. So, it means molecules of liquid water has gained kinetic energy hence, they colloid more rapidly with each other.

As a result, heat will be absorbed by the liquid state of water. Hence, heat will be absorbed. Therefore, phase change from liquid to gas will be endothermic in nature.

Whereas when gaseous state of water will change into liquid state then heat will be released during this process of condensation. As a result, in that case reaction will be exothermic in nature.

5 0
2 years ago
You have a 16.0-oz. (473-mL) glass of lemonade with a concentration of 2.66 M. The lemonade sits out on your counter for a coupl
salantis [7]

<u>Answer:</u> The new concentration of lemonade is 3.90 M

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}     .....(1)

Molarity of lemonade solution = 2.66 M

Volume of solution = 473 mL

Putting values in equation 1, we get:

2.66M=\frac{\text{Moles of lemonade}\times 1000}{473}\\\\\text{Moles of lemonade}=\frac{2.66\times 473}{1000}=1.26mol

Now, calculating the new concentration of lemonade by using equation 1:

Moles of lemonade = 1.26 moles

Volume of solution = (473 - 150) mL = 323 mL

Putting values in equation 1, we get:

\text{New concentration of lemonade}=\frac{1.26\times 1000}{323}\\\\\text{New concentration of lemonade}=3.90M

Hence, the new concentration of lemonade is 3.90 M

7 0
1 year ago
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