Question

How many moles are in 1.50 g of ethylamine, ch3ch2nh2?

Answer 1

Mass =  mass/molar  mass  of   ch3ch2nh2
the   molar  mass  of CH3CH2NH2 =  12  +(1x3)+12+(1 x2)+14+(1x2) =45  g/mol

moles  is therefore  =  1.50g /45g/mol =   0.033 moles

Answer 2

Answer: 0.03 moles

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\textMolar mass}}$    ....(1)

For ethyl amine $CH_3CH_2NH_2$

Mass of ethyl amine $CH_3CH_2NH_2$= 1.50 g

Molar mass of ethyl amine $CH_3CH_2NH_2$= 45 g/mol

Putting values in above equation, we get:

$\text{Moles of ethyl amine}=\frac{1.50g}{45g/mol}=0.03moles$