All categories

2 years ago

What is the mass in grams of 0.48 mol of platinum pt

1 answer:

7 0

To determine the mass, you need first to find the molar mass.
To find it, you have to consult the periodic table and see the atomic mass of each element. If the element is repeated, for example 3 times, you multiple the atomic mass per 3. In this case, the element platinum is not repeated.

molar mass: 195,084 g/mol

To discover the mass, you use a formula that says that moles is calculated by dividing mass by molar mass.
moles: 0.48 mol
molar mass: 195,084 g/mol
mass= x

0,48= x / 195,084
x= 93,64 grams

You might be interested in

A student dissolved 4.00 g of Co(NO3)2 in enough water to make 100. mL of stock solution. He took 4.00 mL of the stock solution

mihalych1998 [28]

Answer:

0.08097 grams of nitrate ions are there in the final solution.

Explanation:

Moles of cobalt(II) nitrate ,n= $\frac{4.00 g}{245 g/mol}=0.01633 mol$

Volume of the cobalt(II) nitrate solution, V = 100.0 mL = 0.1 L

$Molarity=\frac{n}{V(L)}$

Let the molarity of the solution be $M_1$

$M_1=\frac{0.01633 mol}{0.1 L}=0.1633 M$

A students then takes 4 .00 mL of $M_1$ solution and dilute it to 275 ml.

$M_1=0.1633 M$

$V_1=4.00 mL$

$M_2=?$ (molarity after dilution)

$V_2=275 mL$ (after dilution)

$M_1V1=M-2V_2$

$M_2=\frac{M_1V_1}{V_2}=\frac{0.1633 M\times 4.00 mL}{275 mL}=0.002375 M$

Molarity of the of solution after dilution is 0.002375 M.

$Co(NO_3)_2(aq)\rightarrow Co^{2+}(aq)+2NO_3^{-}(aq)$

1 mol of cobalt(II) nitrate gives 2 moles of nitrate ions. Then 0.002375 M solution of cobalt (II) nitrate will give:

$[NO_3^{-}]=\frac{2}{1}\times 0.002375 M=0.004750 M$

Moles of nitrate ions = n

Volume of the solution = 275 mL = 0.275 L

Molarity of the nitrate ions = $[NO_3^{-}]=0.004750 M$

$[NO_3^{-}]=\frac{n}{0.275 L}$

n = 0.001306 mol

Mass of 0.001306 moles of nitrate ions:

0.001306 mol × 62 g/mol= 0.08097 g

0.08097 grams of nitrate ions are there in the final solution.

4 0

2 years ago

A 6.0M solution HCl is diluted to 1.0M How many milliliters of the 6.0M solution would be used to prepare 100.o mL of the dilute

Margarita [4]

Wats r is the most soluble object ever. It is dense

4 0

2 years ago

Read 2 more answers

The highest energy occupied molecular orbital in the f-f bond of the f2 molecule is _____

Morgarella [4.7K]

The basis of finding the answer to this problem is to know the electronic configuration of Fluorine. That would be: [He] 2s² 2p⁵. The valence electrons, which are the outermost electrons of the atom, are the ones that participate in bonding. Since the highest orbital for F is 2p, that means the highest energy occupied would be 2.

3 0

2 years ago

An electron is on a -2.5 eV energy level. The electron is struck by a 2.5 eV photon. What will most likely happen?

kati45 [8]

The correct answer would be C

5 0

2 years ago

A gaseous compound is 30.4% nitrogen and 69.6% oxygen. a 6.06-gram sample of gas occupies a volume of 1.00 liter and exerts a pr

aksik [14]

A gaseous compound is 30.4% nitrogen and 69.6% oxygen by mass. A 5.25-g sample of the gas occupies a volume of 1.00 L and exerts a pressure of 1.26 atm at -4.0°C. Which of the following is its molecular formula?

1) NO2

2) N3O6

3) N2O5

4) N2O4

5) NO

8 0

2 years ago