The calcium chloride needed to produce 1.5 grams of KCl is: 1.12 grams
<h3><em>Further explanation</em></h3>Stoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
In the reaction there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).
Reactions that occur:
CaCl₂ (aq) + K₂CO₃ (aq) → 2 KCl (aq) + CaCO₃ (aq)
From the reaction equation above, the reaction coefficient shows the mole ratio of reagents and products
mol CaCl₂: moles of KCl = 1: 2
relative molecular mass KCl = 74.6
relative molecular mass of CaCl2 = 111
then the mole:
mole KCl = mass: relative molecular mass
mole KCl = 1.5 gram: 74.6
mole KCl = 0.020107
so that
mole CaCl₂ = 1/2. 0.020107
mole CaCl₂ = 0.0100535
So the mass of CaCl2 = mole x relative molecular mass
mass CaCl₂ = 0.0100535 x 111
mass CaCl₂ = 1.12 gram
<h3><em>Learn more</em></h3>moles of water
grams of oxygen required
mass of copper required
Keywords: CaCl2, KCl, mole, mass, relative molecular mass
Explanation:
Dipole moment is defined as the measurement of the separation of two opposite electrical charges.
is a bent shaped molecule with a dipole moment of 1.87.
is also a bent shaped molecule with a dipole moment of 1.10.
is a also a bent shaped molecule and has a negligible dipole moment.
has a dipole moment of 0.29.
Therefore, given molecules are arranged according to their increasing dipole moment as follows.
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Answer: The standard enthalpy of formation of liquid octane is -250.2 kJ/mol
Explanation:
The given balanced chemical reaction is,
First we have to calculate the enthalpy of reaction .
where,
We are given:
Putting values in above equation, we get:
Thus the standard enthalpy of formation of liquid octane is -250.2 kJ/mol