How many grams of calcium chloride are needed to produce 1.50 g of potassium chloride? cacl2(aq) + k2co3(aq) → 2 kcl(aq) + caco3
(aq) 1.12 g 2.23 g 0.896 g 4.47 g?
2 answers:
The calcium chloride needed to produce 1.5 grams of KCl is: 1.12 grams
<h3><em>Further explanation</em></h3>Stoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
In the reaction there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).
Reactions that occur:
CaCl₂ (aq) + K₂CO₃ (aq) → 2 KCl (aq) + CaCO₃ (aq)
From the reaction equation above, the reaction coefficient shows the mole ratio of reagents and products
mol CaCl₂: moles of KCl = 1: 2
relative molecular mass KCl = 74.6
relative molecular mass of CaCl2 = 111
then the mole:
mole KCl = mass: relative molecular mass
mole KCl = 1.5 gram: 74.6
mole KCl = 0.020107
so that
mole CaCl₂ = 1/2. 0.020107
mole CaCl₂ = 0.0100535
So the mass of CaCl2 = mole x relative molecular mass
mass CaCl₂ = 0.0100535 x 111
mass CaCl₂ = 1.12 gram
<h3><em>Learn more</em></h3>moles of water
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mass of copper required
Keywords: CaCl2, KCl, mole, mass, relative molecular mass
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Answer:
The temperature difference of the body after 3 hours = 5.16 K
Explanation:
we know that the number of moles of O₂ inhaled are 0.02 mole/min⁻¹
or, 1.2 mole.h⁻¹
The average heat evolved by the oxidation of foodstuffs is then:
⇒ Q avg = = 7.2 kj.h⁻¹.Kg⁻¹
the heat produced after 3 h would be:
= 7.2 kj. h⁻¹.Kg⁻¹ x 3 h
= 21.6 kj. kg⁻¹
= 21.6 x 10³ j kg⁻¹
We know Qp = Cp x ΔT
Assume the heat capacity of the body is 4.18 J g⁻¹K⁻¹
⇒ ΔT =
⇒ ΔT =
⇒ ΔT = 5.16 K
Answer: The longest wavelength of light that will produce free chlorine atoms in solution is 493 nm.
Explanation:
Energy required to produce free chlorine atoms from one mole of chlorine gas :
= 242.8kJ = (1kJ=1000J)
1 mole = molecules
For molecules = 242,800 Joules
For one molecule of chlorine gas =
According to photoelectric equation:
E = Energy of the photon of light used to produce free chlorine atoms
= frequency of the light used to produce free chlorine atoms
h = Planck's constant =, c = speed of light=
= wavelength of the light used to produce free chlorine atoms
The longest wavelength of light that will produce free chlorine atoms in solution is 493 nm.