Air is transferred from a 75 L tank where the pressure is 125 psi and the temperture is 288 k to a tire with a volume of 6.1 L a
1 answer:
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<u>Answer:</u> The cost is coming out to be $ 1.25
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
Molarity of HCl solution = 0.4 M
Volume of solution = 0.5 L
Putting values in equation 1, we get:
The chemical equation for the reaction of HCl and calcium carbonate follows:
By Stoichiometry of the reaction:
2 moles of HCl reacts with 1 mole of calcium carbonate
So, 0.2 moles of HCl will react with = of calcium carbonate
To calculate the mass of calcium carbonate for given moles, we use the equation:
Molar mass of calcium carbonate = 100 g/mol
Moles of calcium carbonate = 0.1 moles
Putting values in equation 1, we get:
- Calculating the mass of calcium carbonate in 1 container:
We are given:
One container contains eighty 1 g of tablets, this means that in total 80 g of tablets are there.
Every container has 40 % calcium carbonate.
Mass of calcium carbonate in 1 container = 40 % of 80 g =
- Calculating the containers for amount of calcium carbonate that neutralized HCl by using unitary method:
32 grams of calcium carbonate is present in 1 container
So, 10 g of calcium carbonate will be present in = container
- Calculating the cost of turns:
1 container of turns costs $4
So, 0.3125 containers of turns will cost =
Hence, the cost is coming out to be $ 1.25
Answer:
Molar concentration of the weak acid solution is 0.0932
Explanation:
Using the formula:
Where Ca = molarity of acid
Cb = molarity of base = 0.0981 M
Va = volume of acid = 25.0 mL
Vb = volume of base = 23.74 mL
na = mole of acid
nb = mole of base
Since the acid is monopromatic, 1 mole of the acid will require 1 mole of NaOH. Hence, na = nb = 1
Therefore,
Ca = 0.0981 x 23.74/25.0
= 0.093155 M
To 4 significant figure = 0.0932 M