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Alika [10]
2 years ago
15

Air is transferred from a 75 L tank where the pressure is 125 psi and the temperture is 288 k to a tire with a volume of 6.1 L a

nd a pressure of 25 psi. What is the new temperture.
Chemistry
1 answer:
aniked [119]2 years ago
4 0
<h3><u>Answer</u>;</h3>

 = 4.68 K

<h3><u>Explanation</u>;</h3>

According to the combined gas law;

P1V1/T1 = P2V2/T2

Given; P1 = 125 Psi

V1 = 75 L

T1 = 288 K

P2 = 25 PSI

V2 =6.1 L

Therefore;

T2 = P2V2T1/P1V1

    = (25×6.1 ×288)/(125×75)

    = 4.6848

    = 4.68 K

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A 3.5 kg iron shovel is left outside through the winter. The shovel, now orange with rust, is rediscovered in the spring. Its ma
Anton [14]

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a

Explanation:

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2 years ago
Which of the following procedures demonstrates repetition? A. Jeremiah measures the mass of five different strips of metal. He p
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2 years ago
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Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and allowed to reach equilibrium described by the equation N2O4(g) 2N
Amanda [17]

Answer : The correct option is, (a) 0.44

Explanation :

First we have to calculate the concentration of N_2O_4.

\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}

\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M

Now we have to calculate the dissociated concentration of N_2O_4.

The balanced equilibrium reaction is,

                             N_2O_4(g)\rightleftharpoons 2NO_2(aq)

Initial conc.           1.0 M          0

At eqm. conc.     (1.0-x) M    (2x) M

As we are given,

The percent of dissociation of N_2O_4 = \alpha = 28.0 %

So, the dissociate concentration of N_2O_4 = C\alpha=1.0M\times \frac{28.0}{100}=0.28M

The value of x = C\alpha = 0.28 M

Now we have to calculate the concentration of N_2O_4\text{ and }NO_2 at equilibrium.

Concentration of N_2O_4 = 1.0 - x  = 1.0 - 0.28 = 0.72 M

Concentration of NO_2 = 2x = 2 × 0.28 = 0.56 M

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be:

K_c=\frac{[NO_2]^2}{[N_2O_4]}

Now put all the values in this expression, we get :

K_c=\frac{(0.56)^2}{0.72}=0.44

Therefore, the equilibrium constant K_c for the reaction is, 0.44

8 0
2 years ago
12. Penny can knit 4 rows of a sweater in 5
Evgesh-ka [11]

Answer:

6.25 hours

Explanation:

From the question;

  • Penny can knit 4 rows in 5 minutes

We need to determine the time it will take for her to knit 300 rows

4 rows = 5 minutes

300 rows = ?

= (300 × 5 ) ÷ 4

= 375 minutes

But, 1 hour = 60 minutes

Therefore;

= 375 ÷ 60

= 6.25 hours

Thus, it will take penny 6.25 hours to knit 300 rows

8 0
1 year ago
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