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Brut [27]
2 years ago
13

Which of the reactions are spontaneous (favorable)? DHAP − ⇀ ↽ − glyceraldehyde-3-phosphate Δ G = 3.8 kJ / mol DHAP↽−−⇀glycerald

ehyde-3-phosphateΔG=3.8 kJ/mol C 4 H 4 O 5 ⟶ C 4 H 2 O 4 + H 2 O Δ G = 3.1 kJ / mol C4H4O5⟶C4H2O4+H2OΔG=3.1 kJ/mol C 2 H 4 + H 2 Rh ( I ) −−−→ C 2 H 6 Δ G = − 150.97 kJ / mol C2H4+H2→Rh(I)C2H6ΔG=−150.97 kJ/mol glutamate + NAD + + H 2 O ⟶ NH + 4 + α-ketoglutarate + NADH + H + Δ G = 3.7 kcal / mol glutamate+NAD++H2O⟶NH4++α-ketoglutarate+NADH+H+ΔG=3.7 kcal/mol L -malate + NAD + ⟶ oxaloacetate + NADH + H + Δ G = 29.7 kJ / mol -malate+NAD+⟶oxaloacetate+NADH+H+ΔG=29.7 kJ/mol C 6 H 13 O 9 P + ATP ⟶ C 6 H 14 O 12 P 2 + ADP Δ G = − 14.2 kJ / mol
Chemistry
1 answer:
Tpy6a [65]2 years ago
7 0

Answer:

Explanation:

In spontaneous reaction , there is decrease in Gibb's free energy .( Δ G is negative ). Out of given reaction , following reactions have negative Δ G so they are spontaneous.

C ₂ H ₄ + H ₂ Rh ( I ) −−−→ C ₂ H ₆ ,  Δ G = − 150.97 kJ / mol

C ₆ H₁₃O₉ P + ATP ⟶ C ₆ H₁₄ O₁₂ P₂ + ADP ,  Δ G = − 14.2 kJ / mol

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Answer: Option (c) is the correct answer.

Explanation:

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The production of hydrogen gas from water, the tarnishing of a copper penny, charging a cellular phone and burning a plastic water bottle are all chemical reactions.

Whereas a reaction where no change in chemical composition of a substance takes place is known as a physical reaction.

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8 0
2 years ago
a gas that exerts a pressure of 215 torr in a container with a volume of 51.0 mL will exert a pressure of ? torr when transferre
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To calculate the new pressure, we can use Boyle’s law to relate these two scenarios (Boyle’s law is used because the temperature is assumed to remain constant). Boyle’s law is:

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Where “P” is pressure and “V” is volume. The pressure and volume of the first scenario is 215 torr and 51 mL, respectively, and the second scenario has a volume of 18.5 L (18,500 mL) and the unknown pressure - let’s call that “x”. Plugging these into the equation:

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2 years ago
11. A sample contains 25% water and weighs 201 grams. Determine the grams of water in the
77julia77 [94]

Answer:

m_{water}=50.25g

Explanation:

Hello,

In this case, considering that the by-mass percent of water is:

\% m/m=\frac{m_{water}}{m_{sample}}*100\%

Given such percent and the mass of the sample, we can find the mass of water in grams in the sample by solving for it as shown below:

m_{water}=\frac{\%m/m*m_{sample}}{100\%}\\ \\m_{water}=\frac{25\%*201g}{100\%}\\ \\m_{water}=50.25g

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How many grams are in 2.5 pound sample
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