answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brut [27]
1 year ago
13

Which of the reactions are spontaneous (favorable)? DHAP − ⇀ ↽ − glyceraldehyde-3-phosphate Δ G = 3.8 kJ / mol DHAP↽−−⇀glycerald

ehyde-3-phosphateΔG=3.8 kJ/mol C 4 H 4 O 5 ⟶ C 4 H 2 O 4 + H 2 O Δ G = 3.1 kJ / mol C4H4O5⟶C4H2O4+H2OΔG=3.1 kJ/mol C 2 H 4 + H 2 Rh ( I ) −−−→ C 2 H 6 Δ G = − 150.97 kJ / mol C2H4+H2→Rh(I)C2H6ΔG=−150.97 kJ/mol glutamate + NAD + + H 2 O ⟶ NH + 4 + α-ketoglutarate + NADH + H + Δ G = 3.7 kcal / mol glutamate+NAD++H2O⟶NH4++α-ketoglutarate+NADH+H+ΔG=3.7 kcal/mol L -malate + NAD + ⟶ oxaloacetate + NADH + H + Δ G = 29.7 kJ / mol -malate+NAD+⟶oxaloacetate+NADH+H+ΔG=29.7 kJ/mol C 6 H 13 O 9 P + ATP ⟶ C 6 H 14 O 12 P 2 + ADP Δ G = − 14.2 kJ / mol
Chemistry
1 answer:
Tpy6a [65]1 year ago
7 0

Answer:

Explanation:

In spontaneous reaction , there is decrease in Gibb's free energy .( Δ G is negative ). Out of given reaction , following reactions have negative Δ G so they are spontaneous.

C ₂ H ₄ + H ₂ Rh ( I ) −−−→ C ₂ H ₆ ,  Δ G = − 150.97 kJ / mol

C ₆ H₁₃O₉ P + ATP ⟶ C ₆ H₁₄ O₁₂ P₂ + ADP ,  Δ G = − 14.2 kJ / mol

You might be interested in
What is the mass of a sample of NH3 containing 7.20 × 1024 molecules of NH3? 161 grams 187 grams 203 grams 214 grams
Shkiper50 [21]

Answer:

203 grams

Explanation:

<em>It is known that 1.0 mole of a compound contains Avogadro's number of molecules (6.022 x 10²³). </em>

<em><u>Using cross multiplication:</u></em>

1.0 mol contains → 6.022 x 10²³ molecules.

??? mol contains → 7.2 x 10²⁴ molecules.

∴ The no. of moles of (6.3 x 10²⁴ molecules) of NH₃ = (1.0 mol)(7.2 x 10²⁴ molecules)/(6.022 x 10²³ molecules) = 11.96 mol.

<em>∴ The no. of grams of NH₃ present = no. of moles x molar mass </em>= (11.96 mol)(17.0 g/mol) = <em>203.3 g ≅ 203.0 g.</em>

7 0
2 years ago
Read 2 more answers
Express 601 kg as an integer
BigorU [14]
601 expressed as an integer is 3.
An integer refers to a whole number, a number which do not contain any decimal point. 
To express any given number as an integer, just count the number of significant figures in the number and write this down as a whole number.
3 0
2 years ago
Read 2 more answers
What is the temperature change on a 75.0 gram sample of mercury if 480.0 cal of heat are added to it? The specific heat of mercu
Olegator [25]

Answer:

\Delta T=194^oC

Explanation:

Hello,

In this case, in terms of the heat, mass, heat capacity and change in temperature, we can analyze thermal changes as:

Q=mCp\Delta T\\

In such a way, we compute the required change in temperature as shown below:

\Delta T=\frac{Q}{mCp}=\frac{480.0cal}{75.0g*0.033\frac{cal}{g^oC} }  \\\\\Delta T=194^oC

Such change in temperature is positive indicating an increase in the temperature as the involved heat is positive, in means that heat was added to increase the temperature.

Best regards.

6 0
1 year ago
The mass of radium-226 in a sample is found to have decreased from 45.00g to 5.625g in a period of 4800 years.From this informat
yan [13]

Answer:

Half life = 1600 years

Explanation:

Given data:

Total mass of sample = 45.00 g

Mass remain = 5.625 g

Time period = 4800 years

Half life of radium-226 = ?

Solution:

First of all we will calculate the number of half lives passes,

At time zero 45.00 g

At first half life = 45.00 g/ 2= 22.5 g

At 2nd half life = 22.5 g/ 2 = 11.25 g

At 3rd half life = 11.25 g/ 2= 5.625 g

Half life:

Half life = Time elapsed / number of half lives

Half life = 4800 years / 3

Half life = 1600 years

4 0
1 year ago
What is the value of ΔGo in kJ at 25 oC for the reaction between the pair: Mn(s) and Ag+(aq) to give Ag(s) and Mn2+(aq) Use the
Leni [432]

Answer:  -3.8\times 10^{5}J

Explanation:

Mn+2Ag^{+}\rightarrow Mn^{2+}+2Ag

Here Mn undergoes oxidation by loss of electrons, thus act as anode. silver undergoes reduction by gain of electrons and thus act as cathode.

E^0=E^0_{cathode}- E^0_{anode}

Where both E^0 are standard reduction potentials.

E^0_{[Mn^{2+}/Mn]}= -1.18V

E^0_{[Ag^{2+}/Ag]}=+0.80V

E^0=E^0_{[Ag^{+}/Ag]}- E^0_{[Mn^{2+}/Mn]}

E^0=+0.80- (-1.18V)=1.98V

The standard emf of a cell is related to Gibbs free energy by following relation:

\Delta G^0=-nFE^0

\Delta G^0 = gibbs free energy

n= no of electrons gained or lost  = 2

F= faraday's constant

E^0 = standard emf  = 1.98V

\Delta G^0=-2\times 96500\times (1.98)=-3.8\times 10^{5}J

Thus the value of \Delta G^0 is -3.8\times 10^{5}J

8 0
2 years ago
Other questions:
  • 2C6H5COOH + 15O2 → 14CO2 + 6H2O which of the following options gives the correct product:product ratio?
    12·1 answer
  • In this experiment, 0.170 g of caffeine is dissolved in 10.0 ml of water. the caffeine is extracted from the aqueous solution th
    12·1 answer
  • List the number of each type of atom on the left side of the equation 2C10H22(l)+31O2(g)→20CO2(g)+22H2O(g)
    14·1 answer
  • Select the reagent(s) that would efficiently convert the starting material to the product for the following transformations (if
    11·1 answer
  • The Lewis dot notation for two atoms is shown.
    10·2 answers
  • A solution contains 10.0 g pentane, C5H12, 20.0 g hexane, C6H14, and 10.0 g benzene, C6H6. What is the mole fraction of hexane?
    7·1 answer
  • Explain why two thin sweaters feel warmer then one thick sweater​
    10·2 answers
  • When small pieces of manganese oxide were added to a solution of hydrogen peroxide, water and oxygen were produced. Manganese ox
    13·1 answer
  • 3. A 31.2-g piece of silver (s = 0.237 J/(g · °C)), initially at 277.2°C, is added to 185.8 g of a liquid, initially at 24.4°C,
    13·1 answer
  • For double-helix formation, change in Gibbs free energy, ΔG, can be measured to be −54 kJ⋅mol−1 (−13 kcal⋅mol−1) at pH 7.0 in 1
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!