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Elina [12.6K]
2 years ago
8

Which will not appear in the equilibrium constant expression for the reaction below?

Chemistry
1 answer:
n200080 [17]2 years ago
5 0

Answer:

[C] carbon solid

Explanation:

Pure solids and liquids are never included in the equilibrium constant expression because they do not affect the reactant amount at equilibrium in the reaction, thus since your equation has [C] as solid it will not be part of the equlibrium equation.

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The stock concentration of dye is 3.4E-5M. The stock concentration of bleach is 0.36M. Assuming that the reaction goes to comple
Aleks04 [339]

Answer:

0.036 M

Explanation:

To do this, let's mark the dye as D and bleach as B.

We have the concentrations of both, and we already know that they react in a 1:1 mole ratio. The total volume of reaction is 9 + 1 = 10 mL or 0.010 L, and we hava both concentrations.

The problem already states that the dye reacts completely, so this is the limiting reagent, while bleach is the excess.

To know the remaining amount of bleach, we need to do this with the moles. First, let's calculate the initial moles of D and B:

moles D = 3.4x10⁻⁵ * 0.009 = 3.06x10⁻⁷ moles

moles B = 0.36 * 0.001 = 3.6x10⁻⁴ moles

Now that we have the moles, and that we know that all the dye reacts completely, let's see how many moles of bleach are left:

moles of B remaining = 3.6x10⁻⁴ - 3.06x10⁻⁷ = 3.597x10⁻⁴ moles

These are the moles presents of B after the reaction has been made. The concentration of the same will be:

[B] = 3.597x10⁻⁴ / 0.010

[B] = 0.0357

With 2 SF it would be:

[B] = 3.6x10⁻² M

5 0
2 years ago
A cup of gold colored metal beads was measured to have a mass 425 grams. By water displacement, the volume of the beads was calc
Butoxors [25]
If the volume of 425 grams was 48.0 cm³, simply divide

g/cm³ = 425 g/48 cm³ = 8.85 g/cm³

If using water in water displacement, 1 mL = 1 cm³

8.85 g/cm³ = 8.85 g/mL

This density is most closely aligned with that of B. Copper

Hope I helped!
4 0
2 years ago
1‑propanol ( n ‑propanol) and 2‑propanol (isopropanol) form ideal solutions in all proportions. Calculate the partial pressure a
Alex777 [14]

Answer:

y_{prop} = 0.134; y_{iso} = 0.866

The partial pressure of isopropanol = 34.04 Torr; The partial pressure of propanol = 5.26 Torr

Explanation:

For each of the solutions:

mole fraction of isopropanol  (x_{iso}) = 1 - mole fraction of propanol (x_{prop}).

Given: mole fraction of propanol = 0.247. Thus, the mole fraction of isopropanol = 1 - 0.247 = 0.753.

Furthermole, the partial pressure of isopropanol = x_{iso}*vapor pressure of isopropanol = 0.753*45.2 Torr = 34.04 Torr

The partial pressure of propanol = x_{prop}*vapor pressure of propanol = 0.247*20.9 Torr = 5.16 Torr

Similarly,

In the vapor phase,

The mole fraction of propanol (y_{prop}) = \frac{P_{prop} }{P_{prop}+P_{iso}}

Where, P_{prop} is the partial pressure of propanol and P_{iso} is the partial pressure of isopropanol.

Therefore,

y_{prop} = 5.26/(34.04+5.16) = 0.134

y_{iso} = 1 - 0.134 = 0.866

5 0
2 years ago
Boris is interested in conducting his first "real" scientific research. However, he is a bit overwhelmed with all of the possibl
11111nata11111 [884]

Answer:

Questionnaire

Explanation:

This is an instrument for research usually in the form of questions with multiple choice answers with sole purpose of gathering information from respondents for research.

5 0
2 years ago
When filling a burette for a titration, adjust the burette so that______, preferably over a sink. Then,_______to add the titrant
artcher [175]

Answer:

Explanation:

When filling a burette for a titrant, adjust the burette so that the opening is near or below the eye leve preferably over the sink.

Then, use a funnel to add the titrant into the burette.

The titrant should be filled almost to the zero mark.

6 0
2 years ago
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