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GREYUIT [131]
2 years ago
6

The image below represents which of the following (Check all that apply):

Chemistry
2 answers:
natima [27]2 years ago
7 0

One atom

And

Mixure is the answer

lions [1.4K]2 years ago
6 0

Actually its Element, Compound, and mixture

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A chemist has 2.0 mol of methanol (CH3OH). The molar mass of methanol is 32.0 g/mol. What is the mass, in grams, of the sample?
rodikova [14]

Answer:

\boxed {\boxed {\sf D. \ 64 \ grams }}

Explanation:

Given the moles, we are asked to find the mass of a sample.

We know that the molar mass of methanol is 32.0 grams per mole. We can use this number as a fraction or ratio.

\frac{32 \ g \ CH_3OH}{1 \ mol \ CH_3OH}

Multiply by the given number of moles, which is 2.0

2.0 \ mol \ CH_3OH *\frac{32 \ g \ CH_3OH}{1 \ mol \ CH_3OH}

The moles of methanol will cancel each other out.

2.0 \ *\frac{32 \ g \ CH_3OH}{1 }

The denominator of 1 can be ignored.

2.0 * 32 \ g\ CH_3OH

Multiply.

64 \ g \ CH_3OH

There are 64 grams of methanol in the sample.

3 0
1 year ago
Draw the diazonium cation formed when cytosine reacts with nano2 in the presence of hcl.
Sindrei [870]
Answer in the Word document below.
Diazonium compounds are a group of organic compounds sharing a common functional group R−N₂⁺. The process of forming diazonium compounds is called diazotation and usually <span>are prepared by treatment of aromatic amines with </span>nitrous acid<span> and additional acid (hydrochloric acid).
</span>Cytosine is one of the four main bases found in DNA and RNA.
Download docx
7 0
2 years ago
The Lewis dot model of a molecule is shown. A molecule is shown with atoms arranged in the order HCCH. There are three horizonta
denis-greek [22]

Answer:

B)The octet of carbon atom remains incomplete in the molecule.

Explanation:

8 0
2 years ago
An old sample of concentrated sulfuric acid to be used in the laboratory is approximately 98.1 percent h2so4 by mass. calculate
Airida [17]
Basis: 100 mL solution

From the given density, we calculate for the mass of the solution.

                        density  = mass / volume
                        mass = density x volume

                       mass = (1.83 g/mL) x (100 mL) = 183 grams

Then, we calculate for the mass H2SO4 given the percentage.
                   
                      mass of H2SO4 = (183 grams) x (0.981) = 179.523 grams

Calculate for the number of moles of H2SO4,
                  moles H2SO4 = (179.523 grams) / (98.079 g/mol)
                        moles H2SO4 = 1.83 moles

Molarity:
                     M = moles H2SO4 / volume solution (in L)
                         = 1.83 moles / (0.1L ) = 18.3 M

Molality:
                     m = moles of H2SO4 / kg of solvent
                        = 1.83 moles / (183 g)(1-0.983)(1 kg/ 1000 g) = 588.24 m
8 0
2 years ago
How can substance A and B be compared? Choose all that Apply.
77julia77 [94]

I would say the 1.

2. and 4.

Hope this helps!

7 0
2 years ago
Read 2 more answers
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