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SVEN [57.7K]
2 years ago
15

Glucose and amino acids are reabsorbed from the glomerular filtrate by the __________.

Chemistry
1 answer:
AleksandrR [38]2 years ago
5 0

Answer:

Amino acids, along with glucose, are reabsorbed in the glomerular system with a passive or active mechanism as the fluid travels through the entire renal tubular system and enters the circulation again.

Active mechanisms are those that require expenditure of energy, that is, expenditure of the energy currency, while the passive ones do not, they occur through spontaneous non-energy processes such as osmosis, the osmotic gradient and the difference in concentrations in different compartments.

Explanation:

Glomerular filtration is the regulator of the excretion of metabolites and toxic molecules or not necessary for our body. That is why if the amino acid values ​​are high as well as those of glucose in urine, we will be facing a pathology.

If glucose is increased, it is because there is a glycemic peak in blood volume, hence possible diabetes.

And if the amino acids are increased, we could be facing an autoimmune or proteolytic pathology where a large amount of body proteins such as muscle proteins would be breaking down and releasing the amino acids that make it up, this phenomenon usually appears in those people who suffer from rhabdomyolysis in expenses very intense energy sources not appropriate.

On the other hand, glomerular filtration occurs in the kidney and is carried out by the nephron, which is the functional unit of the kidney, within it there is a specific tubular system in collection, absorption and reabsorption, added to the presence of Bowman's capsule.

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Cacodyl, which has an intolerable garlicky odor and is used in the manufacture of cacodylic acid, a cotton herbicide, has a mass
Papessa [141]

Answer:

The molecular formula of cacodyl is C₄H₁₂As₂.

Explanation:

<u>Let's assume we have 1 mol of cacodyl</u>, in that case we'd have 209.96 g of cacodyl and the<u> following masses of its components</u>:

  • 209.96 g * 22.88/100 = 48.04 g C
  • 209.96 g * 5.76/100 = 12.09 g H
  • 209.96 g * 71.36/100 = 149.83 g As

Now we convert those masses into moles:

  • 48.04 g C ÷ 12 g/mol = 4.00 mol C
  • 12.09 g H ÷ 1 g/mol = 12.09 mol H
  • 149.83 g As ÷ 74.92 g/mol = 2.00 mol As

Those amounts of moles represent the amount of each component in 1 mol of cacodyl, thus, the molecular formula of cacodyl is C₄H₁₂As₂.

3 0
2 years ago
What is the density of a piece of metal in g/cm3 if its mass is determined to be 42.20 g and it is in the shape of a cube, with
maria [59]
It's a cube so the volume = edge^3
Volume = 2.5^3 cm^3 = 15.625 cm^3

density = mass / volume = 42.20 / 15.625 = 2.70 You have 3 places of accuracy.

density of object = 2.70 grams / cm^3 <<<<=== answer.
4 0
2 years ago
Read 2 more answers
The name carbohydrate comes from the fact that many simple sugars have chemical formulae that look like water has simply been ad
GREYUIT [131]

Answer:

The maximum mass of water produced is  m__{H_2O}} =116 \ g

Explanation:

From the question we are told that

    The mass of  sucrose is m_s  = 200 \ g

    The chemical formula for  sucrose is  C_{12} H_{22} O_{11}

The chemical equation for the dissociation of sucrose  is

          C_{12} H_{22}O_{4} \to 12C + 11H_2O

The number of moles of  sucrose can be evaluated as

        n =  \frac{m}{Z}

Where Z is the molar mass of sucrose which has a constant value of

      Z  = 342 \ g/mol

So  

    n = \frac{200}{342}

   n =0.585

From the chemical equation one mole of sucrose produces 11 moles of water so  0.585 moles of sucrose will produce x moles of  water

Therefore

          x =  \frac{0.585 * 11}{1}

         x = 6.433 \ moles

Now the mass of water produced is mathematically represented as

         m__{H_2O}} =  x * Z__{H_2O}

 Where  Z__{H_2O} is the molar mass of water with a constant values of  Z__{H_2O}} = 18 \ g/mol

  So  

        m__{H_2O}} =  6.43* 18

       m__{H_2O}} =116 \ g

 

     

     

7 0
2 years ago
Ordinary table sugar is primarily sucrose, which has the chemical formula c12h22o11. calculate the mass percentages of carbon, h
tester [92]
<span>carbon = 42.1% hydrogen = 6.5% oxygen = 51.4% First lookup the molar mass of carbon, hydrogen, and oxygen. mass of carbon = 12.0107 mass of hydrogen = 1.00794 mass of oxygen = 15.999 Now calculate the molar mass of each element in sucrose multiplying the atomic weight of each element by the number of times the element is used. carbon = 12 * 12.0107 = 144.1284 hydrogen = 22 * 1.00794 = 22.17468 oxygen = 11 * 15.999 = 175.989 Calculate the molar mass of sucrose by adding the mass of each element used. 144.1284 + 22.17468 + 175.989 = 342.2921 Finally, calculate the percentage by mass of each element by dividing the mass used for each element by the total mass of sucrose. carbon = 144.1284 / 342.2921 = 0.421068 = 42.1% hydrogen = 22.17468 / 342.2921 = 0.064783 = 6.5% oxygen = 175.989 / 342.2921 = 0.514149 = 51.4%</span>
6 0
2 years ago
A typical aspirin tablet contains 500. mg of c9h8o4. how many moles of c9h8o4 molecules and how many molecules of acetylsalicyli
joja [24]
From the periodic table:
molar mass of carbon = 12 gm
molar mass of hydrogen = 1 gm
molar mass of oxygen = 16 gm

molar mass of <span>acetylsalicylic acid = 9(12) + 8(1) + 4(16) = 180 gm

Number of moles = mass / molar mass = 0.5 / 180 = 2.778 x 10^-3 moles

To get the number of molecules, we multiply the number of moles by Avogadro's number as follows:
number of molecules = </span>2.778x10^-3x6.02x10^23 =1.672 x 10^21 molecules
6 0
2 years ago
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