Which indicator has to be used in order to get an emerald green color at a pH of 9?

The volume of a gas is 36.0 ml at 10.0°c and 4.50 atm. at what temperature (°c) will the gas have a pressure of 3.50 atm and a v

galben [10]

Using the combined gas law, where PV/T = constant, we first solve for PV/T for the initial conditions: (4.50 atm)(36.0 mL)/(10.0 + 273.15 K) = 0.57213.
Remember to use absolute temperature.
For the final conditions: (3.50 atm)(85.0 mL)/T = 297.5/T
Since these must equal, 0.57213 = 297.5/T
T = 519.98 K
Subtracting 273.15 gives 246.83 degC.

5 0

2 years ago

The beaker shown below contains a 0.58 M solution of dye in water. How many moles of dye are there in the beaker?

seropon [69]

According to the equation of molarity:

Molarity= no.of moles / volume per liter of Solution

when we have the molarity=0.58 M and the beaker at 150mL so V (per liter) = 150mL/1000 = 0.150 L

by substitution:
∴ No.of moles = Molarity * Volume of solution (per liter)
= 0.58 * 0.150 = 0.087 Moles

7 0

2 years ago

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The next 3 questions will walk you through using the Henderson-Hasselbalch equation for the following question. For each step pr

kicyunya [14]

Answer:

The pKa is 13.0.

Explanation:

pKa + pKb = 14

Given, Kb of trimethylamine = 6.3 × $10^{-5}$

pKb = - log (6.3 × $10^{-5}$ )

= 1.0

⇒ pKa = 14 - pKb = 14 - 1.0

pKa = 13.0

Check: For most weak acids, pKa ranges from 2 to 13.

8 0

2 years ago

A 3.0-l sample of helium was placed in a container fitted with a porous membrane. half of the helium effused through the membran

Nadya [2.5K]

Answer: M in this equation is molar mass. If A is He and B is O2 then MA = 4 g/mol and MB = 32 g/mol rate A = 1.5L/24hr rate B = 1.5L/?hr and rateA/rateB = ?/24

7 0

2 years ago

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Consider the equilibrium reaction: 3CIO-(aq) ↔ CIO3-(aq) + 2CI-(aq) The equilibrium constant Kc = 3.2 x 103. The following conce

blagie [28]

Answer:

Forward direction

Explanation:

The reaction quotient of an equilibrium reaction measures relative amounts of the products and the reactants present during the course of the reaction at particular point in the time.

Q < Kc , reaction will proceed in forward direction.

Q > Kc , reaction will proceed in backward direction.

Q = Kc , reaction at equilibrium.

It is the ratio of the concentration of the products and the reactants each raised to their stoichiometric coefficients. The concentration of the liquid and the gaseous species does not change and thus is not written in the expression.

Thus, for the reaction:

$3CIO^{-}_{(aq)}\rightleftharpoons CIO_3^{-}_{(aq)}+2Cl^{-}$