Answer:
Explanation:
General reaction of acid in water is as follows:
HCl + H2O = H3O+ + Cl-
Thus Acids increase the concentration of hydronium ions in solution by donating hydrogen ions to water molecules is true
Answer: The correct answer is "B" two bonding domains(or bonding pairs) or two non bonding domains(or lone pairs)
Explanation:
Molecular geometry/structure is a three dimensional shape of a molecule. It is basically an arrangement of atoms in a molecule.It is determined by the central atom, its surrounding atoms and electron pairs.According to VSEPR theory, there are 5 basic shapes of a molecule: linear, trigonal planar, tetrahedral, trigonal bipyramidal and octahedral.
A)Four bonding domains and zero non bonding domains: shape is tetrahedral and bond angle is 109.5°
B)Two bonding domains and two non bonding domains(lone pairs): shape is bent and bond angle is 104.5°
C)Three bonding domains and one non bonding domain: shape is trigonal pyramidal and bond angle is 107°
D)Two bonding domain and zero non bonding domain: shape is linear and bond angle is 107°
E)Two bonding domain and one non bonding domain: bent shape and bond angle is 120°
F)Three bonding domains and zero nonbonding domain: shape is trigonal planar and bond angle is 120°
Hence Two bonding domains and two non bonding domains have the smallest bond angle.
Answer:2
Explanation:
Ba(OH)2 contains two oxygen atoms
BaSO4 contains four oxygen atoms.
This means that barium sulphate contains two more oxygen atoms than barium hydroxide in its formula. This is clearly seen from the two formulae shown above.
Answer : The vapor pressure (in atm) of a solution is, 0.679 atm
Explanation : Given,
Mass of 
= 1.00 kg = 1000 g
Moles of 
= 3.68 mole
Molar mass of = 18 g/mole
Vapor pressure of water = 0.692 atm
First we have to calculate the moles of .
Now we have to calculate the mole fraction of
Now we have to partial pressure of solution.
According to the Raoult's law,
where,
= vapor pressure of solution
= vapor pressure of water = 0.692 atm
= mole fraction of water = 0.938
Therefore, the vapor pressure (in atm) of a solution is, 0.679 atm
Answer:
The temperature of the gas in the 3.00 liter container, must be 150K
Explanation:
Let's apply the Ideal Gas Law, to find out the moles
P . V = n . R . T
1,20 atm . 5L = n . 0,082 L.atm/mol.K . 300 K
(1,20 atm . 5L) / (0,082 mol.K/L.atm . 300 K) = n
6/24,6 mol = n = 0,244 moles
We have the moles now, so let's find the temperature in our new conditions.
P . V = n . R . T
1 atm . 3L = 0,244 moles . 0,082 L.atm/mol.K . T° in K
(1 atm . 3L / 0,244 moles . 0,082 mol.K/L.atm) = T° in K
3/20,008 K = T° in K = 150K
