We are given with
4.35 g Phosphoric acid
5.25 g KOH
3.15 g K3PO4 produced
The reaction is
H3PO4 + 3KOH => K3PO4 + 3H2O
First, convert masses into moles.
Then, determine the limiting reactant.
Next, determine the maximum amount of K3PO4 that can be produced from the limiting reactant.
Lastly, calculate the percent yield by dividing the actual amount produced by the theoretical amount produced.
Answer:
well it turns into N3H12PO4
Explanation:
Answer:
Micky Mo is suffering from respiratory acidosis.
Explanation:
The pCO2 level in micky"s body is higher than normal it means the excess amount of CO2 will reacts with water to generate carbonic acid(H2CO3).
On the other hand according to the question total HCO3- also higher than normal.As a result the excess HCO3- will react with proton to form carbonic acid which is in turn dissociate to generate CO2 and H2O to maintain normal acid base homeostasis.
From that point of view it can be said Micky Mo is suffering from respiratory acidosis.
<h3>The average atomic mass of Iodine : 126.86 amu</h3><h3>Further explanation</h3>
Given
80% 127I, 17% 126I, and 3% 128I.
Required
The average atomic mass
Solution
The elements in nature have several types of isotopes
Atomic mass is the average atomic mass of all its isotopes
Mass atom X = mass isotope 1 . % + mass isotope 2.% + ... mass isotope n.%
Atomic mass of Iodine = 0.8 x 127 + 0.17 x 126 + 0.03 x 128
Atomic mass of Iodine = 101.6 + 21.42 + 3.84
Atomic mass of Iodine = 126.86 amu
Answer:
H2 P4 O1. Explanation: In order to calculate the Empirical formula , we will assume that we have started with 10 g of the compound.
Explanation: