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Musya8 [376]
2 years ago
6

How many ATP are produced from a fatty acid that is 14 carbons long?

Chemistry
1 answer:
fenix001 [56]2 years ago
3 0

Answer:

92 ATP

Explanation:

Fatty acid oxidation results in the formation of large number of ATP molecules. Three important process of fatty acid are activation of the fatty acid, beta oxidation and entry of acetyl CoA in Krebs cycle.

14 carbon fatty acid is Miristic acid. The complete oxidation of Miristic acid results in the formation of 7 acetyl CoA + 6NADH and 6FADH_2

1 Acetyl CoA gives 10 molecules of ATP then 7 acetyl CoA gives 70 molecules of ATP.

1NADH = 2.5 ATP, 6NADH = 15 ATP.

1FADH_2 = 1.5 ATP, 6FADH_2 = 9 ATP.

2 ATP has been consumed in the activation of fatty acid.

Total ATP = 70+15+9-2

=92 ATP.

Thus, the total ATP generated from the oxidation of 14 carbon fatty acid is 92.

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According to the kinetic theory, collisions between molecules in a gas _____.
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8. Explain how Elianto oil is obtained from maize seeds.​
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Answer:

Almost all corn oil is expeller-pressed

Explanation:

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1 year ago
Write the electron configurations for the following ions:
Ket [755]

Answer:

Co²⁺ : 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁷

Sn²⁺ : 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰

Zr⁴⁺ : 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶

Ag⁺ : 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 4d¹⁰

S²⁻ : 1s² 2s² 2p⁶ 3s² 3p⁶

Explanation:

Cobalt (Co): atomic number 27

<u>The electronic configuration of Co in ground state: </u>

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁷

<u>The electronic configuration of Co in +2 oxidation state (Co²⁺) :</u>

1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁷

Tin (Sn): atomic number 50

<u>The electronic configuration of Sn in ground state: </u>

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p²

<u>The electronic configuration of Sn in +2 oxidation state (Sn²⁺) </u>:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰

Zirconium (Zr): atomic number 40

<u>The electronic configuration of Zr in ground state:</u>

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d²

<u>The electronic configuration of Zr in +4 oxidation state (Zr⁴⁺) :</u>

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶

Silver (Ag): atomic number 47

<u>The electronic configuration of Ag in ground state:</u>

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s¹ 4d¹⁰

<u>The electronic configuration of Ag in +1 oxidation state (Ag⁺) :</u>

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 4d¹⁰

Sulphur (S): atomic number 16

<u>The electronic configuration of S in ground state:</u>

1s² 2s² 2p⁶ 3s² 3p⁴

<u>The electronic configuration of S in -2 oxidation state (S²⁻) :</u>

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Answer:

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Explanation:

Protein denaturation is the breakdown of tertiary or quaternary junctions of proteins, which are the easiest to break compared to primary and secondary.

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5 0
2 years ago
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Answer:

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Where; Ea = the activation energy (J/mol)

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T1 = 325°C + 273.15

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T2 = 407°C + 273.15

T2 = 680.15K

Since, k1= 8.58 x 10-9 L/mol, k2= 2.16 x 10-5 L/mol, R= 8.3145 J/Kmol, we can now find Ea

ln(k2/k1) = Ea/R x (1/T1 - 1/T2)

ln(2.16 x 10-5/8.58 x 10-9) = Ea/8.3145 × (1/598.15 - 1/680.15)

ln(2517.4) = Ea/8.3145 × 2.01 × 10^-4

7.831 = Ea(2.417 × 10^-5)

Ea = 3.24 × 10^5 J/mol

8 0
2 years ago
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