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pychu [463]
2 years ago
5

According to Newton's Third Law, what is the equal and opposite force to the downward force of gravity pulling on a man standing

on the beach?
A) the man pulling upward on the earth

B) the force of friction holding the man still

C) the pull of the sun keeping the earth in orbit

D) the surrounding air pressure keeping the man in equilibrium
Chemistry
1 answer:
KIM [24]2 years ago
6 0

Answer: Option (A) is the correct answer.

Explanation:

Newton's third law states that when one body exerts a force on a second body, the second body simultaneously exerts a force equal in magnitude and opposite in direction on the first body.

In short we can say that every action has an equal and opposite reaction.

For example, when we hit a wooden table hardly with our hands then we are applying a force on the table and on the other hand table is applying a force in the opposite direction on our hand due to which we get hurt.

Therefore, when force of gravity pulls the man in downward direction then man pulling upward on the earth is applying a force in opposite direction of gravitational pull.

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Moist to wet as warm is to:<br><br> Luke<br> Boiling or<br> Steamy
Vinvika [58]

Answer:steamy

Explanation:

8 0
2 years ago
Give the number of significant figures in this number: 40.00
Tatiana [17]

A significant figure is every symbol that made the number itself.

In this case, the number 40.00 has four figures but only two of them are significant 40, this is because you haven't got any more decimals than the first zero.

If you have a case with zeros in front, you take to the first non zero digits.

For example, 0.071004 you wold express as 0.071 and those 7, and 1 are the significant ones.

4 0
2 years ago
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The correct answer(reported to the proper number of significant figures)to the following is
LenKa [72]
to the proper number of significant figures) to the following? (12.67+19.2)(3.99)/(1.36+ 11.366).
8 0
1 year ago
Given equilibrium partial pressures of PNO2= 0.247 atm, PNO = 0.0022atm, and PO2 = 0.0011 atm calculate the equilibrium constant
maxonik [38]
Answer 1:
Equilibrium constant (K) mathematically expressed as the ratio of the concentration of products to concentration of reactant. In case of gaseous system, partial pressure is used, instead to concentration.

In present case, following reaction is involved:

                        2NO2    ↔      2NO + O2

Here, K = \frac{[PNO]^2[O2]}{[PNO2]^2}

Given: At equilibrium, <span>PNO2= 0.247 atm, PNO = 0.0022atm, and PO2 = 0.0011 atm
</span>
Hence,  K = \frac{[0.0022]^2[0.0011]}{[0.247]^2}
                 = 8.727 X 10^-8

Thus, equilibrium constant of reaction = 8.727 X 10^-8
.......................................................................................................................

Answer 2:
Given: <span>PNO2= 0.192 atm, PNO = 0.021 atm, and PO2 = 0.037 atm.

Therefore, Reaction quotient = </span>\frac{[PNO]^2[O2]}{[PNO2]^2}
                                              = \frac{[0.021]^2[0.037]}{[0.192]^2}
                                              = 4.426 X 10^-4.

Here, Reaction quotient > Equilibrium constant.

Hence, <span>the reaction need to go to reverse direction to reattain equilibrium </span>
5 0
2 years ago
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Hector claims that a single sodium ion and a single oxygen ion do not bond together to form a stable binary ionic compound. Is h
levacccp [35]

Answer:

C

Explanation:

Looking at the periodic table, we can see that sodium is in group 1, so a sodium ion would be Na⁺, with a charge of +1. Oxygen is in group 16, so an oxygen ion would be O²⁻, with a charge of -2.

A compound formed only by a single sodium ion and a single oxygen ion would thus have a charge of -1, and in order to have a stable ionic compound its charge must be zero.

8 0
1 year ago
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